我在尝试使用AutoMapper的复杂类型时遇到了问题。
我有两个对象,一个域和一个ViewModel在我的视图中使用;
ViewModel
public class RegisterCoupleModel
{
[Required(ErrorMessage = "campo obrigatório")]
[Display(Name = "Primeiro nome", Order = 0, GroupName = "Noivo")]
[StringLength(60)]
public string FistNameGroom
{
get;
set;
}
[Required(ErrorMessage = "campo obrigatório")]
[Display(Name = "Último nome", Order = 1, GroupName = "Noivo")]
[StringLength(60)]
public string LastNameGroom
{
get;
set;
}
[Required(ErrorMessage = "campo obrigatório")]
[RegularExpression(@"^[w-.]+@([w-]+.)+[w-]{2,4}$", ErrorMessage = "Formato de email inválido.")]
[DataType(DataType.EmailAddress)]
[Remote("IsEmailAvailable", "Validation", "", ErrorMessage = "este email já está sendo usado por outro usuário.")]
[Display(Name = "Email", Order = 2, GroupName = "Noivo")]
[StringLength(180)]
public string EmailGroom
{
get;
set;
}
[Required(ErrorMessage = "campo obrigatório")]
[Display(Name = "Primeiro nome", Order = 0, GroupName = "Noiva")]
[StringLength(60)]
public string FistNameBride
{
get;
set;
}
[Required(ErrorMessage = "campo obrigatório")]
[Display(Name = "Último nome", Order = 1, GroupName = "Noiva")]
[StringLength(60)]
public string LastNameBride
{
get;
set;
}
[Required(ErrorMessage = "campo obrigatório")]
[RegularExpression(@"^[w-.]+@([w-]+.)+[w-]{2,4}$", ErrorMessage = "Formato de email inválido.")]
[DataType(DataType.EmailAddress)]
[Remote("IsEmailAvailable", "Validation", "", ErrorMessage = "este email já está sendo usado por outro usuário.")]
[Display(Name = "Email", Order = 2, GroupName = "Noiva")]
[StringLength(180)]
public string EmailBride
{
get;
set;
}
[Required(ErrorMessage = "campo obrigatório")]
[Display(Name = "Url")]
[RegularExpression(@"^[a-zA-Z0-9_-.+]{5,22}$", ErrorMessage = "Chave inválida")]
[StringLength(22, MinimumLength = 5, ErrorMessage = "A chave deve ter entre {0} e {1} caracteres.")]
[Remote("IsKeywordAvaliable", "Validation")]
public string UrlKeyword
{
get;
set;
}
[Display(Name = "Voce é humano?")]
[UIHint("ReCaptcha")]
public string ReCaptcha
{
get;
set;
}
}
域对象
public class Couple
{
[Key]
public Guid Id { get; set; }
public string UrlKeyword { get; set; }
public virtual Partner Groom { get; set; }
public virtual Partner Bride { get; set; }
public DateTime Marriage { get; set; }
public DateTime Dating { get; set; }
public DateTime Engagement { get; set; }
public virtual ICollection<User> Users { get; set; }
}
如果你看一下,你会发现我的对象Couple
域具有属性Bride
和Groom
,它们实际上是相同类型。
如何将域对象Couple
映射到RegisterCoupleModel
?
这里我只写了:
在settings中,automapper尝试做如下操作:
CreateMap<RegisterCoupleModel, Couple>()
.ForMember(dest => dest.Bride.User.FirstName, opt => opt.MapFrom(source => source.FistNameBride))
.ForMember(dest => dest.Bride.User.LastName, opt => opt.MapFrom(source => source.LastNameBride))
.ForMember(dest => dest.Bride.User.Email, opt => opt.MapFrom(source => source.EmailBride))
.ForMember(dest => dest.Groom.User.FirstName, opt => opt.MapFrom(source => source.FistNameGroom))
.ForMember(dest => dest.Groom.User.LastName, opt => opt.MapFrom(source => source.LastNameGroom))
.ForMember(dest => dest.Groom.User.Email, opt => opt.MapFrom(source => source.EmailGroom));
但是显示如下错误:
表达式'dest => dest. bride . user。FirstName'必须解析为顶级成员。参数名称:lambdaExpression
我知道这需要尝试使用嵌套类型映射属性的行为。
但是我怎么能把RegisterCoupleModel
映射到Couple
和两个属性Bride
和Groom
是相同的类型?
我在StackOverflow上发现了一个问题,看起来像这样,但它帮助了我。
我要做的是封装属性FirstNameBride, LastNameBride, EmailBride, firstname新郎, lastname新郎, email新郎到一个嵌套的视图模型类型,让我们说PersonDetails
:
public class PersonDetails
{
public string FirstName { get; set; }
public string LastName { get; set; }
public string Email { get; set; }
}
并相应地更新父VM:
public class RegisterCoupleModel
{
public PersonDetails GroomDetails { get; set; }
public PersonDetails BrideDetails { get; set; }
}
然后您可以提供从PersonDetails
到User
(或任何类型的新郎)的映射。用户):
Mapper.CreateMap<PersonDetails,User>();
请注意我是如何得到如此显式的属性映射的->因为字段在源和目标中具有相同的名称,所以不需要显式映射。只要有可能,就尽量这样做。少代码->好代码。
那么除了上面的映射之外,只需这样做:
Mapper.CreateMap<RegisterCoupleModel, Couple>();
并且AutoMapper将看到RegisterCoupleModel
有两个PersonDetails
对象,看到它已经有一个映射定义,然后自动使用它。
应该可以(我以前做过)。
你不应该总是使用平面视图模型,在必要的地方嵌套它们(比如重用字段)。