我有一个键:列表对的字典。列表是字符串的列表,但它们必须是整数。下面是我开始的一个例子:
dictionary = {
"P4021a": ["1","2","3","4","5"],
"P4019a": ["1","2","3","4","5"],
"P4013a": ["1","2","3","4","5"]
}
我正在努力实现以下目标:
dictionary = {
"P4021a": [1,2,3,4,5],
"P4019a": [1,2,3,4,5],
"P4013a": [1,2,3,4,5]
}
以下是我迄今为止所尝试的:
new_dict = {}
for key in dictionary.keys():
new_dict[key] = dictionary[int(key)]
我收到一个错误,说明int((不能对列表进行操作。因此,我还尝试在每个列表中添加迭代。
new_dict = {}
for key in dictionary.keys():
new_dict[key] = dictionary[[int(value) for value in dictionary.values() for i in range(5)]]
我也试过:
new_dict = {}
for key in dictionary.keys():
new_dict[key] = dictionary[map(int,key)]
感谢您的帮助。
for i in dictionary:
dictionary[i]=map(int,dictionary[i])
print dictionary
您可以简单地从map
到int
。
Bhargav指出,在Python3中,map
返回map object
而不是list
,因此需要使用
list(map(int,dictionary[i]))
for key in dictionary:
dictionary[key] = [int(val) for val in dictionary[key]]