Bluebird promise library:是 .map 和 .filter 并行运行的

Question

我正在尝试用蓝鸟承诺编写一堆异步fs调用。除了我担心性能之外，一切都很好。我无法判断.map和.filter函数是并行执行还是顺序执行。这是我的代码：

var Promise = require('bluebird'),
  fs = Promise.promisifyAll(require('fs'));
module.exports = getDirListing;
function getDirListing(path) {
  function toFullPath(file) {
    return path + file;
  }
  function onlyDirs(file) {
    return fs.statAsync(file).then(function(file) {
      return !file.isFile();
    });
  }
  function ignoreHidden(name) {
    return !(name.substring(0,1) === '.');
  }
  function toModuleNames(dir) {
    return dir.replace(path, '');
  }
  return fs.readdirAsync(path)
    .map(toFullPath)
    .filter(onlyDirs)
    .map(toModuleNames)
    .filter(ignoreHidden);
}

我特别关心对onlyDirs的调用，因为这正在进行一堆异步fs.stat调用，并且可以/应该并行。我尝试查看他们的 api 文档，但我没有看到任何关于并行化的内容。

注意：不幸的是，我目前无法使用 ECMAScript6 生成器。

此外，欢迎在此处提供有关性能的任何其他指示。

Answer 1

fs.stat 调用是并发完成的，您可以使用以下命令进行验证：

var id = 0;
function onlyDirs(file) {
  var d = id++;
  return fs.statAsync(file).then(function(file) {
    console.log("returned from stat call %d", d);
    return !file.isFile();
  });
}

returned from stat call 0
returned from stat call 1
returned from stat call 2
returned from stat call 3
returned from stat call 5
returned from stat call 4
returned from stat call 6
returned from stat call 7
returned from stat call 8
returned from stat call 10
returned from stat call 11
returned from stat call 14
returned from stat call 13
returned from stat call 9
returned from stat call 15
returned from stat call 18
returned from stat call 17
returned from stat call 16
returned from stat call 12

请注意，代码最初不起作用，我不得不修改它：

var Path = require("path");
function toFullPath(file) {
    return Path.join(path, file);
}