Django tastypie:在单个TastyPie资源中添加多种型号

Question

我在Django应用程序中具有以下模型。BasicInfo和advellyInfo表使用客户表的ID列链接到客户表，该表是这些表中的Customer_id列。

对于每个客户，地址INFO或BASICINFO表中可以有多个条目。

class Customer(models.Model):
    id = models.IntegerField(primary_key=True)
    joining_dtm = models.DateTimeField()
    isactive = models.IntegerField()
    class Meta:
        db_table = u'Customer'

class Addressinfo(models.Model):
    id = models.IntegerField(primary_key=True)
    apt_num = models.CharField(max_length=135, blank=True)
    street = models.CharField(max_length=135, blank=True)
    street_2 = models.CharField(max_length=135, blank=True)
    city = models.CharField(max_length=135, blank=True)
    country = models.CharField(max_length=135, blank=True)
    postalcode = models.CharField(max_length=135, blank=True)
    customer_id = models.ForeignKey(Customer)
    class Meta:
        db_table = u'AddressInfo'
class Basicinfo(models.Model):
    id = models.IntegerField(primary_key=True)
    name = models.CharField(max_length=135, blank=True)
    about = models.CharField(max_length=135, blank=True)
    website = models.CharField(max_length=135, blank=True)
    customer_id = models.ForeignKey(Customer)
    class Meta:
        db_table = u'BasicInfo'

我如何创建一个TastyPie资源，这将使我能够将所有客户表作为API提供。

资源返回的JSON对象可能与ID 12，

的客户相似。

{
   "id": 12, 
   "joining_dtm": "2012-10-25T07:06:54.041528", 
   "resource_uri": "/public-api/api/v0.1a/customer/1/", 
   "AddressInfo": [
      {    
          "id":22,
          "apt_num": "54",
          "street": "Avondale Place",
          "street_2": "",
          "city": "Chicago",
          "country": "India",
          "postalcode": "600059",
          "customer_id": 12
       },
      {
          "id":96,
          "apt_num": "11",
          "street": "Infinite Loop",
          "street_2": "",
          "city": "Cupertino",
          "country": "USA",
          "postalcode": "123456",
          "customer_id": 12
       }
    ],
   "BasicInfo": [
      {
          "id": 33,
          "name": "My Full Name",
          "about": "Blah Blah Blah",
          "website": "http://google.com",
          "customer_id": 12
       },
      {
          "id": 147,
          "name": "My New Name",
          "about": "More Blah Blah",
          "website": "http://gmail.com",
          "customer_id": 12
       }
    ]
}

Answer 1

如果您只是要求列出所有客户的API：

/public-api/api/v0.1a/customer/?format=json

应该给你。否则，下面是我认为您要问的 - 如何在查看客户的端点

时如何设置资源以显示基本信息/地址信息

在您的api.py中：

class CustomerResource(ModelResource):
    # The 2nd parameter is tricky:
    # Try suffixing with nothing, 's', or '_set'
    # e.g. 'addressinfo', 'addressinfos', 'addressinfo_set'
    addressinfos = fields.ToManyField('your_app_name.api.AddressInfoResource', 'addressinfo_set', Full=True)
    basicinfos = fields.ToManyField('your_app_name.api.BasicInfoResource', 'basicinfo_set', Full=True)
    class Meta:
        queryset = Customer.objects.all()
        resource_name = 'customer'

class AddressInfoResource(ModelResource):
    class Meta:
        queryset = Addressinfo.objects.all()
        resource_name = 'addressinfo'

class BasicInfoResource(ModelResource):
    class Meta:
        queryset = Basicinfo.objects.all()
        resource_name = 'basicinfo'

当然，根据需要在每个资源上添加身份验证/授权。