php在添加新输入字段后没有正确验证或发送

Question

php新手又带着一些小问题回来了，我已经研究了几个小时了，但还是找不到解决方案。

我已经把这个表单用于另一个表单，它工作得很好，但这次我添加了输入字段的nric，率和一个复选框"同意"。这是3个不验证并阻止表单发送的字段。如有任何帮助，不胜感激

代码如下:

//Retrieve form data. 
//GET - user submitted data using AJAX
//POST - in case user does not support javascript, we'll use POST instead
$name = ($_GET['name']) ? $_GET['name'] : $_POST['name'];
$phone = ($_GET['phone']) ? $_GET['phone'] : $_POST['phone'];
$email = ($_GET['email']) ?$_GET['email'] : $_POST['email'];
$nric = ($_GET['nric']) ?$_GET['nric'] : $_POST['nric'];
$rate = ($_GET['rate']) ?$_GET['rate'] : $_POST['rate'];
$comment = ($_GET['comment']) ?$_GET['comment'] : $_POST['comment'];
$agree = ($_GET['agree']) ?$_GET['agree'] : $_POST['agree'];

//flag to indicate which method it uses. If POST set it to 1
if ($_POST) $post=1;
//Simple server side validation for POST data, of course, you should validate the email
if (!$name) $errors[count($errors)] = 'Please enter your Full name Surname in UPPERCASE.';
if (!$phone) $errors[count($errors)] = 'Please enter your contact number - e.g. [phone].';
if (!$email) $errors[count($errors)] = 'Please enter your email.';
if (!$nric) $errors[count($errors)] = 'Please enter your Business No or NRIC if not a business.'; 
if (!$rate) $errors[count($errors)] = 'Please enter the rate you wish to pay (in RM)'; 
if (!$comment) $errors[count($errors)] = 'Please describe what you require this person for and when.'; 
if (!$agree) $errors[count($errors)] = 'Please agree to the Booking Fee.';
//if the errors array is empty, send the mail
if (!$errors) {
        //recipient - replace your email here
        $to = '[e-mail]'; 
        //sender - from the form
        $from = $name . ' <' . $email . '>';
        //subject and the html message
        $subject = 'Message from ' . $name; 
        $message = 'Name: ' . $name . '<br/><br/>
                             Phone: ' . $phone . '<br/><br/>
                             Email: ' . $email . '<br/><br/>
                             NRIC: ' . $nric . '<br/><br/>
                             Rate: ' . $rate . '<br/><br/>
                             Agree: ' . $agree . '<br/><br/>
                             Message: ' . nl2br($comment) . '<br/>';
//send the mail
$result = sendmail($to, $subject, $message, $from);
//if POST was used, display the message straight away
if ($_POST) {
    if ($result) echo 'Thank you! We have received your message.';
    else echo 'Sorry, unexpected error. Please try again later';
//else if GET was used, return the boolean value so that 
//ajax script can react accordingly
//1 means success, 0 means failed
} else {
    echo $result;   
}
    //if the errors array has values
    } else {
        //display the errors message
        for ($i=0; $i<count($errors); $i++) echo $errors[$i] . '<br/>';
        echo '<a href="index.html">Back</a>';
        exit;
    }

    //Simple mail function with HTML header
    function sendmail($to, $subject, $message, $from) {
        $headers = "MIME-Version: 1.0" . "rn";
        $headers .= "Content-type:text/html;charset=iso-8859-1" . "rn";
        $headers .= 'From: ' . $from . "rn";
        $result = mail($to,$subject,$message,$headers);
        if ($result) return 1;
        else return 0;
    }

Answer 1

你确定不是像缺少引号那么简单吗?

看

$to = [e-mail]';

应该是

$to = '[e-mail]'; // ** Missing leading quote on string