graphql query to json query

给定这个 GraphQL 示例，如何在 Javascript 中使用 JSON 执行类似的请求？

使用 GraphQL，示例中的查询为：

{
  trip(
    from: {place: "NSR:StopPlace:5533" },
    to: {place:"NSR:StopPlace:5532"}
  ) 
    {
    tripPatterns{duration}
  } 
}

根据文档，要查询的 URL https://api.entur.io/journey-planner/v2/graphql 。

以下是我在Javascript中尝试的内容：

var url = "https://api.entur.io/journey-planner/v2/graphql";
var tripquery = 
{
    trip: 
    {
        __args: {
            from : {place :"NSR:StopPlace:5533" },
            to : {place :"NSR:StopPlace:5532" }                     
        },
        tripPatterns: {
            duration : true             
        }
    }
};
function jsonQuery(){
    var qry = JSON.stringify(tripquery);
    var url_qry = url + "?query=" + qry;
    var xhttp = new XMLHttpRequest();
    xhttp.open("POST", url_qry, true);
    xhttp.setRequestHeader("Content-Type", "application/json");
    xhttp.onreadystatechange = function(){
        console.log("onreadystatechange");
        if(xhttp.readyState === 4 && xhttp.status === 200){
            console.log("json-query-OK");
            console.log(xhttp.responseText);
        }
        else{
            console.log("xhttp.status      : " + xhttp.status);
            console.log("xhttp.statusText  : " + xhttp.statusText);
            console.log("xhttp.readyState  : " + xhttp.readyState);
            console.log("xhttp.responseType: " + xhttp.responseType);
            console.log("xhttp.responseText: " + xhttp.responseText);
            console.log("xhttp.responseURL : " + xhttp.responseURL);
            console.log("json-not-ok");
        }
    };

    xhttp.send();
    console.log("query sent");
}

上面的代码将在控制台中产生此输出：

query sent
api.entur.io/journey-planner/v2/graphql?query={%22trip%22:{%22__args%22:{%22from%22:{%22place%22:%22NSR:StopPlace:5533%22},%22to%22:{%22place%22:%22NSR:StopPlace:5532%22}},%22tripPatterns%22:{%22duration%22:true}}}:1 POST https://api.entur.io/journey-planner/v2/graphql?query={%22trip%22:{%22__args%22:{%22from%22:{%22place%22:%22NSR:StopPlace:5533%22},%22to%22:{%22place%22:%22NSR:StopPlace:5532%22}},%22tripPatterns%22:{%22duration%22:true}}} 400 (Bad Request)
query.js:29 onreadystatechange
query.js:35 xhttp.status      : 400
query.js:36 xhttp.statusText  : Bad Request
query.js:37 xhttp.readyState  : 2
query.js:38 xhttp.responseType: 
query.js:39 xhttp.responseText: 
query.js:40 xhttp.responseURL : https://api.entur.io/journey-planner/v2/graphql?query={%22trip%22:{%22__args%22:{%22from%22:{%22place%22:%22NSR:StopPlace:5533%22},%22to%22:{%22place%22:%22NSR:StopPlace:5532%22}},%22tripPatterns%22:{%22duration%22:true}}}
query.js:41 json-not-ok
query.js:29 onreadystatechange
query.js:35 xhttp.status      : 400
query.js:36 xhttp.statusText  : Bad Request
query.js:37 xhttp.readyState  : 3
query.js:38 xhttp.responseType: 
query.js:39 xhttp.responseText: No query found in body
query.js:40 xhttp.responseURL : https://api.entur.io/journey-planner/v2/graphql?query={%22trip%22:{%22__args%22:{%22from%22:{%22place%22:%22NSR:StopPlace:5533%22},%22to%22:{%22place%22:%22NSR:StopPlace:5532%22}},%22tripPatterns%22:{%22duration%22:true}}}
query.js:41 json-not-ok
query.js:29 onreadystatechange
query.js:35 xhttp.status      : 400
query.js:36 xhttp.statusText  : Bad Request
query.js:37 xhttp.readyState  : 4
query.js:38 xhttp.responseType: 
query.js:39 xhttp.responseText: No query found in body
query.js:40 xhttp.responseURL : https://api.entur.io/journey-planner/v2/graphql?query={%22trip%22:{%22__args%22:{%22from%22:{%22place%22:%22NSR:StopPlace:5533%22},%22to%22:{%22place%22:%22NSR:StopPlace:5532%22}},%22tripPatterns%22:{%22duration%22:true}}}
query.js:41 json-not-ok

Json 对象中的__args是我从在线示例中得到的，但我还没有真正理解它。

也许我不确定要搜索什么，但我找不到一些关于如何将这个 GraphQL 查询转换为 JSON 对象的好解释。

我遇到了同样的问题，我是这样做的：

{
  c_con_tic_PTF(dz: CR, docmanId: 123) {
    docmanId
    dz
    data
  }
}

我尝试在OS X中将此请求作为curl命令发送如何在OS X中使用CURL：

curl 
      -X POST 
      -H "Content-Type: application/json" 
      --data '{ "query": "{  c_con_tic_PTF(docmanId: 123, dz: CR) { docmanId, dz, data }}" }' 
   *my-graphicQL endpoint url*

我

得到了我想要的回应。

所以你想从你的 graphQL 查询中制作这样的东西：

{ "query": "{  cz_atlascon_etic_PTF(docmanId: 123, dz: CR) { docmanId, dz, data }}" }

现在只需使用 JS 发送请求。如果它以任何方式对您有所帮助，这就是我的请求在 Java 中的样子：

HttpRequest mainRequest =
HttpRequest.newBuilder()
.uri(URI.create("my graphQL endpoint"))
.POST(HttpRequest.BodyPublishers.ofString("{ "query": "{  c_con_tic_PTF(docmanId: 123, dz: CR) { docmanId, dz, data }}" }"))
.build();

在Javascript中做到这一点的一种方法是使用fetch api。像这样的事情是我过去的做法。您可以通过复制下面的代码，然后将其粘贴到 Chrome 开发工具中并运行它来对其进行测试。

async function makeGraphQlQuery(urlToResource) {
    const queryObject = {
      query:
        '{ trip( from: {place: "NSR:StopPlace:5533" }, to: {place:"NSR:StopPlace:5532"}) {tripPatterns{duration}} }',
    };
    const response = await fetch(urlToResource, {
      method: 'POST',
      headers: { 'Content-Type': 'application/json' },
      body: JSON.stringify(queryObject),
    });
    const json = response.json();
    return json;
}
async function sendAsync() { 
  const res = await makeGraphQlQuery('https://api.entur.io/journey-planner/v2/graphql');
  console.log(res); 
}
sendAsync().catch(err => console.log('Error in query', err));

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