打开网址并在IOS 9 / 10中打开

Question

-UIApplication.shared.openURL(url)
-UIApplicartion.shared.open(url,options: [:],completionHandler: nil)

我可以在 iOS9 和 iOS10 中使用这两个选项吗？

iOS9 和/或 iOS10 是否支持UIApplication.shared.openURL(url)？

Answer 1

你可以

试试这个

guard let url = URL(string: "http://www.google.com") else {
  return //be safe
}
if #available(iOS 10.0, *) {
    UIApplication.shared.open(url)
} else {
    UIApplication.shared.openURL(url)
}

Answer 2

是的，您必须通过将它们置于这样的状态来使用两者，

func open(scheme: String) {
  if let url = URL(string: scheme) {
    if #available(iOS 10, *) { // For ios 10 and greater
      UIApplication.shared.open(url, options: [:],
        completionHandler: {
          (success) in
           print("Open (scheme): (success)")
       })
    } else { // for below ios 10.
      let success = UIApplication.shared.openURL(url)
      print("Open (scheme): (success)")
    }
  }
}

Answer 3

guard let url = URL(string: "https://www.google.com/") else { return }
        if #available(iOS 10.0, *) {
            UIApplication.shared.open(url)
        } else {
            // Fallback on earlier versions
            let svc = SFSafariViewController(url: url)
            present(svc, animated: true, completion: nil)
        }

当我想在iOS 9及更高版本的Safari浏览器中打开URL时，我使用了这个。