如何在Siebel中的BS中编写脚本以在输出中存储多个记录

Question

我有一个场景，其中lov具有很高的值为" package" and type =" to_new_package"，我必须获取低点的值，而低点有8个记录。我必须显示每个记录的所有8个记录及其组件成本。所有这些都应作为将输出的显示消息消失。请让我知道该怎么做。

var ssearchexp =" [type] ='" " package_plan" "'''an and [high] ='" potpageplan "''';setSearchExpr(ssearchexp(;executeQuery((;var isrecord = firstrecord((;while(isRecord({slow = getfieldValue(" low"(;outputs.setProperty(" new_package_plan"，slow(;outputs.setProperty("错误代码"，" 00"(;outputs.setProperty(" errordesc"，" success"(;i = i 1;isrecord = nextrecord((;}

这仅存储1个记录...我希望显示所有八个记录！

Answer 1

这应该让您开始

var sSearchExp = "[Type]= '" + "PACKAGE_PLAN" + "' AND [High] = '" + PACKAGEPLAN + "'";
var Slow = "";
SetSearchExpr(sSearchExp);
ExecuteQuery();
var isRecord = FirstRecord();
while (isRecord) {
    Slow += GetFieldValue("Low");
    Slow += " ";
    i = i + 1;
    isRecord = NextRecord();
}
Outputs.SetProperty("NEW_PACKAGE_PLAN", Slow);
Outputs.SetProperty("ErrorCode", "00");
Outputs.SetProperty("ErrorDesc", "Success");

Answer 2

此示例代码将向下打印值：

var boAsset = TheApplication().GetBusObject("List Of Values");
var bcAsset = boAsset.GetBusComp("List Of Values");
with (bcAsset)
{
    ActivateField("Value");
    var sSearchExp = "[Type]= 'AAG_TABLE_TYPE'";
    var Slow = "";
    SetSearchExpr(sSearchExp);
    ExecuteQuery();
    var isRecord = FirstRecord();
    while (isRecord)
    {
        Slow += GetFieldValue("Value");
        Slow += "n";
        isRecord = NextRecord();
    }
    TheApplication().RaiseErrorText(Slow);
}

输出：

AAG Account
AAG Holdg
AAG Portf
AAG Txn

将Slow += "n";更改为Slow += " ";将侧面打印值。

希望您在这里得到技巧。