我知道如何在Java中做到这一点,但是C#无法正常工作。我确定我错过了一些明显的东西。如您所见,如果宠物不是狗,我想将宠物扔到狗。我认为沮丧是对的,但也许不是。 问题是这一行Console.WriteLine("{0,12}t {1}t {2,10:C}t {3}t {4}", Name, Type, Price, Weight, Sound(), AKCRegistration);
它不允许我访问我所指的 getter。
这是我的主要课程
static void Main(string[] args)
{
Pet[] pets = new Pet[5];
pets[0] = new Dog("King", 55, PET_TYPE.Canine, "akc1000", 1000);
pets[1] = new Dog("Princess", 25, PET_TYPE.Canine, "akc1000", 2000);
pets[2] = new Dog("Spike", 25, PET_TYPE.Canine, "akc1000", 25);
pets[3] = new Cat("Missy", 15, PET_TYPE.Feline, 50);
pets[4] = new Cat("Mr Boogangle", 5, PET_TYPE.Feline, 30);
//for (int i = 0; i < pets.Length; i++)
//{
// Console.WriteLine($"{pets[i]}");
//}
for each (Pet pet in pets)
{
if (pet is Dog)
{
Dog Pet = (Dog) pet;
Console.WriteLine("{0,12}t {1}t {2,10:C}t {3}t {4}", Name, Type, Price, Weight, Sound(), AKCRegistration);
}
}
这是我的狗课
class Dog: Pet
{
private string aKCregistration;
public Dog(string name, int weight, PET_TYPE type, string AKC, double price) : base(name, weight, type, price)
{
this.aKCRegistration = AKC;
if (aKCRegistration == "")
{
aKCRegistration = "Mutt";
}
}
public int AKCRegistration { get; set; }
public override string Sound()
{
return "Woof, Woof";
}
public override string ToString()
{
return String.Format("{0,12}t {1}t {2,10:C}t {3}t {4}", Name, Type, Price, Weight, Sound());
}
}
我的宠物班
public enum PET_TYPE
{
Canine, Feline
}
public abstract class Pet
{
internal string name;
internal int weight;
internal PET_TYPE type;
internal double price;
public Pet(string name, int weight, PET_TYPE type, double price)
{
this.name = name;
this.weight = weight;
this.type = type;
this.price = price;
}
public string Name
{
get { return name; }
set { name = value; }
}
public int Weight
{
get { return weight; }
set { weight = value; }
}
public double Price
{
get { return price; }
set { price = value; }
}
public PET_TYPE Type
{
get { return type; }
set { type = value; }
}
public override string ToString()
{
return String.Format("{0,12}t {1}t {2,10:C}t {3}t {4}", Name, Type, Price, Weight, Sound());
}
public abstract string Sound();
} // end class pet
我包括了除我的猫类之外的所有内容,如果您需要查看,请告诉我。
您没有使用实例Pet
变量引用它们,在这种情况下,当您从类外部访问它们时,您需要在它们上指定实例变量以告知您正在访问哪个对象的状态,例如:
Console.WriteLine("{0,12}t {1}t {2,10:C}t {3}t {4}",
Pet.Name,
Pet.Type,
Pet.Price,
Pet.Weight,
Pet.Sound(),
Pet.AKCRegistration);
当您在Dog
中覆盖ToString
成员函数时,您还可以像这样调用它:
string petString = Pet.ToString();
当您访问类中的那些时Dog
这意味着您正在引用当前对象,无论哪个调用ToString
方法,因此它无需显式指定任何实例即可工作,您可以将其视为:
Console.WriteLine("{0,12}t {1}t {2,10:C}t {3}t {4}",
this.Name,
this.Type,
this.Price,
this.Weight,
this.Sound(),
this.AKCRegistration);
但是我们不需要显式添加this
因为编译器会处理这个问题。