我有一个列表视图,每行都有一个文本字段和edittext字段。我让他们都在屏幕上打架。当我通过接听电话、返回等方式恢复活动时,edittext字段中的输入与最初输入的内容不匹配。我想知道如何设置onresume或保存的即时状态来防止这种情况,并确保正确的输入位于正确的edittext字段中。
这是我正在使用的代码。
public class editview extends ListActivity {
private dbadapter mydbhelper;
private PopupWindow pw;
public static int editCount;
public static ListView listView;
public ItemAdapter adapter;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
mydbhelper = new dbadapter(this);
mydbhelper.open();
View footer = getLayoutInflater().inflate(R.layout.footer_layout, null);
ListView listView = getListView();
listView.addFooterView(footer);
showResults();
}
//Populate view
private void showResults (){
Cursor cursor = mydbhelper.getUserWord();
startManagingCursor(cursor);
String[] from = new String[] {dbadapter.KEY_USERWORD};
int[] to = new int[] {R.id.textType};
adapter = new ItemAdapter(this, R.layout.edit_row, cursor,
from, to);
adapter.notifyDataSetChanged();
this.setListAdapter(adapter);
editCount = adapter.getCount();
adapter.notifyDataSetChanged();
}
//footer button
public void onClick(View footer){
final MediaPlayer editClickSound = MediaPlayer.create(this, R.raw.button50);
editClickSound.start();
if (ItemAdapter.inputValues.containsValue("")){
Toast.makeText(this, "Please fill in all fields", 1000).show();
}else{
startActivity(new Intent("wanted.pro.madlibs.OUTPUT"));
};
}
...
}
@Override
protected void onResume() {
super.onResume();
}
@Override
protected void onPause() {
super.onPause();
}
}
//custom cursor adapter
class ItemAdapter extends SimpleCursorAdapter {
private LayoutInflater mInflater;
private Cursor cursor;
static Map<Integer, String> inputValues = new LinkedHashMap<Integer, String>();
static String oldText;
public ItemAdapter(Context context, int layout, Cursor cursor, String[] from,
int[] to) {
super(context, layout, cursor, from, to);
this.cursor = cursor;
mInflater = LayoutInflater.from(context);
}
static class ViewHolder implements TextWatcher {
protected TextView text;
protected EditText edittext;
protected int position;
public void afterTextChanged(Editable editable) {
Log.e(String.valueOf(position), "Position in array");
inputValues.put(position, editable.toString());
}
public void beforeTextChanged(CharSequence s, int start, int count,
int after) {
// TODO Auto-generated method stub
}
public void onTextChanged(CharSequence s, int start, int before,
int count) {
// TODO Auto-generated method stub
}
}
@Override
public View getView(final int position, View convertView, ViewGroup parent) {
ViewHolder holder;
if (convertView == null) {
convertView = mInflater.inflate(R.layout.edit_row, null);
holder = new ViewHolder();
holder.text = (TextView) convertView.findViewById(R.id.textType);
holder.edittext = (EditText) convertView.findViewById(R.id.editText);
holder.edittext.addTextChangedListener(holder);
holder.position = position;
convertView.setTag(holder);
} else {
holder = (ViewHolder) convertView.getTag();
}
cursor.moveToPosition(position);
int label_index = cursor.getColumnIndex("userword");
String label = cursor.getString(label_index);
holder.text.setText(label);
oldText = inputValues.get(position);
holder.edittext.setText(oldText == null ? "" : oldText);
return convertView;
}
}
首先,ListViews中的EditText是一个很大的麻烦,以防您开始遇到问题。其次,您似乎在任何时候都没有保存inputValue
字符串。至少您应该序列化onSaveInstanceState()
中的值,并在onCreate()
中读回它们。您也不应该将它们存储在适配器中。您应该有一个适当的"模型"(一个带有标签和输入值的对象)来支持适配器。SimpleCursorAdapter不太适合并行修改数据。