将SHA1密码转换为二进制形式

Question

我有一个数据库，密码用SHA1加密，我需要将它们转换为SHA1二进制形式，并用base64编码，我如何获得它？

这就是我所拥有的：

# echo -n "password" | openssl sha1
5baa61e4c9b93f3f0682250b6cf8331b7ee68fd8

这就是我需要的：

# echo -n "password" | openssl sha1 -binary | base64
W6ph5Mm5Pz8GgiULbPgzG37mj9g=

Answer 1

require 'digest/sha1'
require 'base64'
Base64.encode64(Digest::SHA1.digest('password'))
# => "W6ph5Mm5Pz8GgiULbPgzG37mj9g=n"

这增加了一个新行，所以你可能需要使用

Base64.encode64(Digest::SHA1.digest('password')).chop
# => "W6ph5Mm5Pz8GgiULbPgzG37mj9g="

或者更简单，正如@FrederickCheung所建议的：

Digest::SHA1.base64digest('password')

---

编辑

当您只有SHA-1编码密码的十六进制字符串时，请执行

require 'base64'
pass = "5baa61e4c9b93f3f0682250b6cf8331b7ee68fd8"
Base64.encode64([pass].pack('H*')).chop
# => "W6ph5Mm5Pz8GgiULbPgzG37mj9g="

或者你甚至可以绕过base64库，只依赖pack:

[[pass].pack('H*')].pack('m0')
# => "W6ph5Mm5Pz8GgiULbPgzG37mj9g="

Answer 2

Python 3方法：

import sys, base64
def hex_to_b64(word):
    number = int(word, base=16)
    bytestr = number.to_bytes(20, 'big')
    b64 = base64.b64encode(bytestr).decode('ascii')
    return b64
if __name__ == '__main__':
    for word in sys.argv[1:]:
        print(hex_to_b64(word))

它给出

localhost-2:coding $ python3 shaswitch.py 5baa61e4c9b93f3f0682250b6cf8331b7ee68fd8
W6ph5Mm5Pz8GgiULbPgzG37mj9g=

Answer 3

为什么要求助于python；OP通缉令：

% openssl sha1 -binary <(echo -n 'password') | base64
W6ph5Mm5Pz8GgiULbPgzG37mj9g=