PHP WebSocket ZMQ - 聊天操作 - 将数据发送给特定用户

Question

im正在处理基于Symfony 2.2.11的PHP项目，我安装了与以下教程相关的socketo http://socketo.me/docs/install 以使我的聊天脚本正常工作。

ServerCommand.php//启动 WebSocket 服务器的命令行的代码

$oLoop = Factory::create();
    // Listen for the web server to make a ZeroMQ push after an ajax request
    $oContext = new Context($oLoop);
    $oPull = $oContext->getSocket(ZMQ::SOCKET_PULL);
    // LET IT 127.0.0.1
    $oPull->bind('tcp://127.0.0.1:5555'); // Binding to 127.0.0.1 means the only client that can connect is itself
    $oPull->on('message', array($oChat, 'onMessage'));
    // Set up our WebSocket server for clients wanting real-time updates
    $oWebSock = new Server($oLoop);
    $oWebSock->listen(7979, '0.0.0.0'); // Binding to 0.0.0.0 means remotes can connect
    $webServer = new IoServer(
        new HttpServer(
            new WsServer(
                new WampServer(
                    $oChat
                )
            )
        ),
        $oWebSock
    );
    $oLoop->run();

将

消息添加到数据库后：消息控制器.php

....
// This is our new stuff
        $oContext = new ZMQContext();
        $oSocket = $oContext->getSocket(ZMQ::SOCKET_PUSH, 'PushMe');
        $oSocket->connect("tcp://mydomain:5555");
        $aData = array(
            'topic'         => 'message',
            'sUsername'     => $oUserCurrent->getUsername(),
            'sMessage'      => $sMessage
        );
        $oSocket->send(json_encode($aData));
.....

聊天服务：聊天.php

/**
 * A lookup of all the topics clients have subscribed to
 */
public function onSubscribe(ConnectionInterface $conn, $topic) 
{
    // When a visitor subscribes to a topic link the Topic object in a  lookup array
    $subject = $topic->getId();
    $ip = $conn->remoteAddress;
    if (!array_key_exists($subject, $this->subscribedTopics)) 
    {
        $this->subscribedTopics[$subject] = $topic;
    }
    $this->clients[] = $conn->resourceId;
    echo sprintf("New Connection: %s" . PHP_EOL, $conn->remoteAddress);
}
/**
 * @param string JSON'ified string we'll receive from ZeroMQ
 */
public function onMessage($jData) 
{
    $aData = json_decode($jData, true);
    var_dump($aData);
    if (!array_key_exists($aData['topic'], $this->subscribedTopics)) {
        return;
    }
    $topic = $this->subscribedTopics[$aData['topic']];
    // This sends out everything to multiple users, not what I want!!
    // re-send the data to all the clients subscribed to that category
    $topic->broadcast($aData);
}

接收数据的JS代码：消息.html.twig ：

var conn = new ab.Session(
                    'ws://mydomain:7979' // The host (our Ratchet WebSocket server) to connect to
                  , function() {            // Once the connection has been established
                        conn.subscribe('message', function(topic, data) 
                        {
                            console.log(topic);
                            console.log(data);
                        });
                    }
                  , function() {            // When the connection is closed
                        console.warn('WebSocket connection closed');
                    }
                  , {                       // Additional parameters, we're ignoring the WAMP sub-protocol for older browsers
                        'skipSubprotocolCheck': true
                    }
                );

所以一切都很完美，当我发送一条新消息时，它会转到数据库，然后它降落在聊天页面。

问题：数据落在JS脚本所在的位置，结果是所有用户都可以获得相同的记录消息

问：如何使数据登陆特定用户页面？

谢谢

Answer 1

你在后端使用Ratchet，对吧？

所以，这里有你需要的很好的例子：

http://socketo.me/docs/hello-world

您应该将客户端连接保留在属性$clients（而不是资源 ID 的集合！因此，您可以从此集合中选择一个元素，并仅向此客户端发送消息。

例：

public function onSubscribe(ConnectionInterface $conn, $topic) 
{
    // When a visitor subscribes to a topic link the Topic object in a  lookup array
    $subject = $topic->getId();
    $ip = $conn->remoteAddress;
    if (!array_key_exists($subject, $this->subscribedTopics)) 
    {
        $this->subscribedTopics[$subject] = $topic;
    }
    $this->clients[] = $conn; // you add connection to the collection
    $conn->send("Hello new user!"); // you send a message only to this one user
}