F#，在不使用临时变量的情况下通过管道转发匹配案例

Question

我想在不使用临时变量或 lambda 的情况下将变量通过管道转发到匹配情况。这个想法：

let temp =
    x 
    |> Function1
    |> Function2
    // ........ Many functions later.
    |> FunctionN
let result =
    match temp with
    | Case1 -> "Output 1"
    | Case2 -> "Output 2"
    | _ -> "Other Output"

---

我希望写一些类似于以下内容的东西：

// IDEAL CODE (with syntax error)
let result =
    x
    |> Function1
    |> Function2
    // ........ Many functions later.
    |> FunctionN
    |> match with   // Syntax error here! Should use "match something with"
        | Case1 -> "Output 1"
        | Case2 -> "Output 2"
        | _ -> "Other Output"

---

我拥有的最接近的东西是使用 lambda 的以下内容。但我认为下面的代码也不是那么好，因为我仍在"命名"临时变量。

let result =
    x
    |> Function1
    |> Function2
    // ........ Many functions later.
    |> FunctionN
    |> fun temp -> 
        match temp with   
        | Case1 -> "Output 1"
        | Case2 -> "Output 2"
        | _ -> "Other Output"

---

另一方面，我可以直接用一大块代码替换"temp"变量：

let result =
    match x 
          |> Function1
          |> Function2
          // ........ Many functions later.
          |> FunctionN with
    | Case1 -> "Output 1"
    | Case2 -> "Output 2"
    | _ -> "Other Output"

是否可以编写类似于代码#2的代码？还是我必须选择代码 #3 或 #4？谢谢。

Answer 1

let result =
    x
    |> Function1
    |> Function2
    // ........ Many functions later.
    |> FunctionN
    |> function  
        | Case1 -> "Output 1"
        | Case2 -> "Output 2"
        | _ -> "Other Output"