我试图从三个查询中获取总数 qryBOM
、 qryLabour
和 qryLaser
并将它们列在一行中。
我创建了一个qryTotals
过滤器,这是我的代码:
SELECT
Sum(tempTotalLabour) AS TotalLabour,
Sum(tempTotalCost) AS TotalCost,
Sum(tempTotalLaser) AS TotalLaser,
[TotalLabour] + [TotalCost] + [TotalLaser] AS ProductCost
FROM
(
SELECT
Sum([qryLabour].[Labour Mins]) AS tempTotalLabour,
Sum([qryLabour].[$ Cost]) AS tempTotalCost,
Sum([qryLabour].[Laser Mins]) AS tempTotalLabour
FROM
qryLabour
union all
SELECT
Sum([qryBOM].[Labour Mins]) AS tempTotalLabour,
Sum([qryBOM].[$ Cost]) AS tempTotalCost,
Sum([qryBOM].[Laser Mins]) AS tempTotaMaterial
FROM
qryBOM
union all
SELECT
Sum([qryLaser].[Labour Mins]) AS tempTotalLabour,
Sum([qryLaser].[$ Cost]) AS tempTotalCost,
Sum([qryLaser].[Laser Mins]) AS tempTotalLaser
FROM
qryLaser
) AS TotalTable;
但是我Duplicate Output Alias - 'tempTotalLabour'
收到错误.请有人帮助我解决我出错的地方,以便我可以解决这个问题并为将来学习。
干杯克里斯
你用了两次tempTotalLabour
我做了一次尝试,如下所示
SELECT
Sum(tempTotalLabour) AS TotalLabour,
Sum(tempTotalCost) AS TotalCost,
Sum(tempTotalLaser) AS TotalLaser,
Sum(tempTotalLabour) + Sum(tempTotalCost) + Sum(tempTotalLaser) AS ProductCost
FROM
(
SELECT
Sum([qryLabour].[Labour Mins]) AS tempTotalLabour,
Sum([qryLabour].[$ Cost]) AS tempTotalCost,
Sum([qryLabour].[Laser Mins]) as tempTotalLaser
FROM
qryLabour
union all
SELECT
Sum([qryBOM].[Labour Mins]) AS tempTotalLabour,
Sum([qryBOM].[$ Cost]) AS tempTotalCost,
Sum([qryBOM].[Laser Mins]) AS tempTotalLaser
FROM
qryBOM
union all
SELECT
Sum([qryLaser].[Labour Mins]) AS tempTotalLabour,
Sum([qryLaser].[$ Cost]) AS tempTotalCost,
Sum([qryLaser].[Laser Mins]) AS tempTotalLaser
FROM
qryLaser
) AS TotalTable;