如何在带引号的子字符串中仅用点替换逗号?

Question

>假设我有一个字符串：

$string =  'apple, cat, dog, "0,445",symphony, "0,454"';

我想要的输出是：

$string =  'apple, cat, dog, "0.445",symphony, "0.454"';

Answer 1

您可以使用preg_replace

$string = preg_replace('/("d+),(d+")/','$1.$2',$string);

Answer 2

试试这个正则表达式： https://regexr.com/3uvj0

$string = preg_replace('/(".)(,)(.*")/', '$1.$3', $string);

Answer 3

请根据您的要求找到解决方法，

$string = 'apple, cat, dog, "0.445",symphony, "0,454"';
$array = str_replace('*comma*', ',', explode(',',preg_replace_callback('|"[^"]+"|', function ($matches) {return str_replace(',', '*comma*', $matches[0]);}, $string)));
foreach ($array as $key => $value) {
$array[$key] = str_replace(',', '.', $value);
}
$string = implode(",", $array);

我参考了链接。 这是您的工作代码。