Android 2D Array

Question

我试图显示基于RadioButtons的数组的内容。我使用两组按钮。按钮应该指向我数组中的[x, y]。需要显示阵列的String值(使用Toast)

是的，我是新手，但我试着找出几个类似的例子，但运气不好。

public class MainActivity extends Activity {
    String[][] tipSize = {
            {"N/A","N/A","Pink","Lt Blue","Purple","Yellow","Brown","Orange","Tan","Blue","White","Beige"},
            {"N/A","Pink","Lt Blue","Purple","Yellow","Brown","Orange","Green","Tan","Blue","White","Beige"},
            {"N/A","N/A","Pink","Purple","Turquoise","Yellow","Green","Tan","Blue","White","Red","No Tip"},
            {"Pink","Lt Blue","Purple","Yellow","Orange","Green","Tan","Blue","Red","Beige","Gray","N/A"},
            {"Pink","Lt Plue","Purple","Orange","Green","Tan","Blue","White","Beige","Black","Gray","N/A"},
            {"Pink","Lt Blue","Yellow","Brown","Orange","Green","Tan","Blue","White","Beige","Black","N/A"},
            {"Pink","Lt Blue","Yellow","Brown","Tan","Blue","White","Red","Beige","Black","No Tip","N/A"},
            {"Pink","Lt Blue","Purple","Yellow","Orange","Green","Tan","Blue","Red","Beige","Gray","N/A"},
    };
private RadioGroup dispenser,ounce_pg;
private RadioButton disp,o_pg;
String tip = "";
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    Button finishBtn = (Button) findViewById(R.id.button1);
    finishBtn.setOnClickListener (new View.OnClickListener() {      
        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub
            MainActivity.this.showit(); 
        }
    });     
}
protected void showit() {
    // TODO Auto-generated method stub
    disp = (RadioButton) findViewById(R.id.dispenser);
    o_pg = (RadioButton) findViewById(R.id.ounce_pg);
    tip = String tipSize [disp,o_pg];
    // tip is the displayed answer (Color of tip), tipSize[][] is the Array, disp is RadioButton 1 - o_pg is Radio Button 2 values. 
    Toast.makeText(MainActivity(),tip,Toast.LENGTH_LONG).show();
}
}

Answer 1

一种快速而肮脏的方法是创建一个简单的字符串数组，其中包含一个分隔的字符串，将第二个值分组在一起，然后使用split函数，该函数本身返回一个字符串数组来获取单个值。

String [] allTips = {"a;b;c", "d;e;f"};
String [] sometips = alltips[1].split(";")
String tip = sometips[2];

会产生字母f

Answer 2

这一行有很多问题:

 tip = String tipSize [disp,o_pg];

1. [disp,o_pg]应该是[disp][o_pg]，因为访问2D数组是通过array [x][y]完成的

2. String tipSize没有意义，你不能在这里声明类型。如果你做了(String)，它将是一个强制转换，这将是好的(但这将是多余的，因为你有一个String数组-从String转换成String不做任何事情)。

3. disp和o_pg应为int。

这是因为当访问索引时，你不能将Object传递给数组，数组不会为你"搜索"。这意味着你需要弄清楚你想要进入哪些职位，并把它们传递出去。还要记住索引从0开始，而不是从1开始。

一个可编译的例子是:

tip = tipSize [0][0]; //first element of the first array ("N/A")