乘法表与二维数组

Question

我需要制作一个从1 * 1到12 * 12的乘法表。我有这个工作，但它需要在13列的格式，看起来像下面的图表，真的很感谢任何帮助。

    1    2    3    4    5    6    7    8    9    10    11    12
1   1    2    3    4    5    ...
2   2    4    6    8    10   ....
3
4
5
6
...

目前代码:

public class timetable {
    public static void main(String[] args) {
         int[][] table = new int[12][12];
            for (int row=0; row<12; row++){
              for (int col=0; col<12; col++){
                table[row][col] = (row+1) * (col+1);
              }
            }
            for (int row = 0; row < table.length; row++) {
                for (int col = 0; col < table[row].length; col++) {
                   System.out.printf("%6d", table[row][col]);
                }
                System.out.println();
             }
    }
}

Answer 1

在打印表格之前打印列标题，并在每行开头打印行标题。您可以使用下面的代码:

int[][] table = new int[12][12];
for (int row=0; row<12; row++){
  for (int col=0; col<12; col++){
    table[row][col] = (row+1) * (col+1);
  }
}
// Print column headings
System.out.printf("%6s", "");
for (int col = 0; col < table[0].length; col++) {
    System.out.printf("%6d", col+1);
}
System.out.println();
for (int row = 0; row < table.length; row++) {
    // Print row headings
    System.out.printf("%6d", row+1);
    for (int col = 0; col < table[row].length; col++) {
       System.out.printf("%6d", table[row][col]);
    }
    System.out.println();
 }

Answer 2

这只打印9x9时间表，如果您需要将其更改为12x12，则只需将代码中的数字从"9"更改为"12"，并在系统输出中添加更多"----"行以匹配它

这包括" * |"one_answers"----"…我想这可能对其他人有帮助

输出:9 x9时间表

public class timetable2DArray
{
    public static void main(String[] args) 
    {
        int[][] table = new int[9][9];
        for (int row=0; row<9; row++)
        {
          for (int col=0; col<9; col++)
      {
        table[row][col] = (row+1) * (col+1);
      }
    }
    // Print column headings
    System.out.print("   * |");
    for (int col = 0; col < table[0].length; col++) 
    {
        System.out.printf("%4d", col+1);
    }
    System.out.println("");
    System.out.println("------------------------------------------");
    for (int row = 0; row < table.length; row++) 
    {
        // Print row headings
        System.out.printf("%4d |", row+1);
        for (int col = 0; col < table[row].length; col++) 
        {
           System.out.printf("%4d", table[row][col]);
        }
        System.out.println();
     }
}

}

Answer 3

    int [][] A = new int[5][5];
    int [][] B = new int[5][5];
    for (int row = 0; row < A.length; row++) {
        System.out.println();
        for (int col = 0; col < A.length; col++) {
            B[row][col] = (row+1)*(col+1);
            System.out.print("t");
            System.out.printf("%2d", B[row][col]);
        }
    }

Answer 4

您可以实现一个timesTable()方法。这是我的代码，你可以随意修改。

//main driver
public static void main(String[] args) {
    int[][] data; //declaration
    data = timesTable(4,6); //initialisation
    for (int row = 0; row < data.length ; row++)
    {
        for (int column = 0; column < data[row].length; column++)
        {
            System.out.printf("%2d ",data[row][column]);
        }
        System.out.println();
    }
}
//method
public static int[][] timesTable(int r, int c)
{
    int [][] arr = new int[r][c];
    for (int row = 0; row < arr.length ; row++)
    {
        for (int column = 0; column < arr[row].length; column++)
        {
            arr[row][column] = (row+1)*(column+1);
        }
    }
    return arr;
}