如何删除分页中的重复项

Question

table1 & table2：

表

1和表2 http://aftabfarda.parsfile.com/1.png

SELECT     *
FROM         (SELECT DISTINCT dbo.tb1.ID, dbo.tb1.name, ROW_NUMBER() OVER (ORDER BY tb1.id DESC) AS row
FROM         dbo.tb1 INNER JOIN
                      dbo.tb2 ON dbo.tb1.ID = dbo.tb2.id_tb1) AS a
WHERE     row BETWEEN 1 AND 7
ORDER BY id DESC

结果：

结果。。。http://aftabfarda.parsfile.com/3.png

（id 11 重复 3 次）

我怎么能有这个输出：

ID  name    row
--  ------  ---
11  user11  1
10  user10  2
9   user9   3
8   user8   4
7   user7   5
6   user6   6
5   user5   7

Answer 1

您可以在使用子查询row_number之前应用 distinct：

select  *
from    (
        select  row_number() over (order by tbl.id desc) as row
        ,       *
        from    (
                select  distinct t1.ID
                ,       tb1.name
                from    dbo.tb1 as t1
                join    dbo.tb2 as t2
                on      t1.ID = t2.id_tb1
                ) as sub_dist
        ) as sub_with_rn
where   row between 1 and 7

Answer 2

或者，对于

@Andomar的建议，您可以使用DENSE_RANK而不是ROW_NUMBER并首先对行进行排名（在子查询中），然后应用DISTINCT（在外部查询中）：

SELECT DISTINCT
  ID,
  name,
  row
FROM (
  SELECT
    t1.ID,
    t1.name,
    DENSE_RANK() OVER (ORDER BY t1.ID DESC) AS row
  FROM dbo.tb1 t1
    INNER JOIN dbo.tb2 t2 ON t1.ID = t2.id_tb1
) AS a
WHERE row BETWEEN 1 AND 7
ORDER BY ID DESC

相似，但不完全相同，尽管两者都可能归结为相同的查询计划，但我只是不确定。我认为值得测试。

当然，您也可以尝试半连接而不是正确的连接，以 IN 或 EXISTS 的形式，首先防止重复：

SELECT
  ID,
  name,
  row
FROM (
  SELECT
    ID,
    name,
    ROW_NUMBER() OVER (ORDER BY ID DESC) AS row
  FROM dbo.tb1
  WHERE ID IN (SELECT id_tb1 FROM dbo.tb2)
  /* Or:
  WHERE EXISTS (
    SELECT *
    FROM dbo.tb2
    WHERE id_tb1 = dbo.tb1.ID
  )
  */
) AS a
WHERE row BETWEEN 1 AND 7
ORDER BY ID DESC