为什么我不能将getimagesize php与此图像一起使用?
对于此图像,我可以得到getimagesize php,工作良好。
<?PHP
$source = "https://i.pinimg.com/736x/da/7a/19/da7a19a0c3daabe579ecca21d1ae32c3--felt-wool-felting-projects.jpg";
$dimension = getimagesize($source);
$width = $dimension[0];
$height = $dimension[1];
echo $width;
echo "<BR>";
echo $height;
?>
但是,对于此图像,为什么我无法获得getimagesize php?
<?PHP
$source = "https://shorebread.com/wp-content/uploads/2016/07/kitty-cat-reaching_138482216-2000x500.jpg";
$dimension = getimagesize($source);
$width = $dimension[0];
$height = $dimension[1];
echo $width;
echo "<BR>";
echo $height;
?>
我该如何在每个图像上使用getimagesize php?
可能是网站不允许"热链接"或阻止PHP的用户代理。
如果您尝试从URL获取数据,您将获得 http/1.1 403 forbidden forbidden 响应:
php > $dimension = getimagesize($source);
PHP Warning: getimagesize(https://shorebread.com/wp-content/uploads/2016/07/kitty-cat-reaching_138482216-2000x500.jpg):
failed to open stream: HTTP request failed! HTTP/1.1 403 Forbidden
in php shell code on line 1
如果首先下载图像,然后从磁盘上执行同样的操作:
php > $dimension = getimagesize("kitty-cat-reaching_138482216-2000x500.jpg");
php > print_r($dimension);
Array
(
[0] => 2000
[1] => 500
[2] => 2
[3] => width="2000" height="500"
[bits] => 8
[channels] => 3
[mime] => image/jpeg
)
因此,并非getimagesize
在所有图像上都无法使用。它无法下载图像本身。