RSA-2048 解密不起作用 - PKCS1_OAEP "Incorrect decryption."

Question

代码应该设置一个服务，侦听来自投票网站的连接。它是一个监听来自外部(客户端)连接的服务器。当客户端连接时，客户端等待发送版本号。一旦我的服务器/侦听器发送了版本号，客户机就会响应一个256字节的块，该块是使用我提供的公钥加密的RSA 2048位。然后必须对该块进行解码，(稍后)我将读取内容。我被卡住了，我无法得到它的解密:

我得到这个:

开始连接…

connection from ('50.28.6.244'， 35338)

发送版本号…

接收加密块

回溯(最近一次调用):

文件" votellistener .py"，第97行，

主(private_key)

文件" votellistener .py"，第49行，在Main

decodedfile = decode_msg(data, privatekey)

文件"voteListener.py"，第58行，在decode_msg

ciphertext = cipher.decrypt(msg)

File "C:Python27libsite-packagesCryptoCipherPKCS1_OAEP.py"，第227行，在解密

引发ValueError("不正确的解密。")

ValueError: Incorrect decryption.

C: 用户桌面 STEXAS vote>暂停

按任意键继续…

我代码:

import socket
from Crypto.PublicKey import RSA
from Crypto.Cipher import PKCS1_OAEP
from os import path

def Main(privatekey):
    host = "0.0.0.0"
    port = 8192
    version = "VOTIFIER 1.9"
    print("starting connection...")
    while True:
        s = socket.socket()
        s.bind((host, port))
        s.listen(1)
        c, addr = s.accept()
        print("connection from %s" % str(addr))
        print("sending version number...")
        c.send(version)
        c.send('n')
        print("receiving encrypted block")
        data = c.recv(256)
        c.close()
        s.close()
        decodedfile = decode_msg(data, privatekey)
        with open("votes.txt", 'wb') as f:
            f.write(decodedfile)
        print("File writen")

def decode_msg(ciphertext, priv_key):
    cipher = PKCS1_OAEP.new(priv_key)
    msg = cipher.decrypt(ciphertext)
    return msg

def read_private_key():
    with open("keysmykey.pem", 'rb') as f:
        data = f.read()
    key = RSA.importKey(data)
    return key

def generate_key_pair():
    """Generates a 2048 bit RSA key pair and saves the keys to disk"""
    pair = RSA.generate(2048)
    f = open("keysmykey.pem", "wb")  # private key
    f.write(pair.exportKey('PEM'))
    f.close()
    pub_key = pair.publickey().exportKey(format='PEM')
    keytext = str(pub_key).strip("-----BEGIN PUBLIC KEY-----").strip("-----END PUBLIC KEY-----").replace('n', "")
    with open("keyspublic.txt", 'wb') as f:  # the plain text public key for providing to server list
        f.write(keytext)
    with open("keyspublic.pem", 'wb') as f:  # public key
        f.write(pub_key)

if __name__ == "__main__":
    private_key = None
    if not path.exists("keysmykey.pem"):
        generate_key_pair()
    if path.exists("keysmykey.pem"):
        private_key = read_private_key()
    if private_key is not None:
        Main(private_key)
    else:
        print("Error with Keys... no key was generated or found!")

Answer 1

客户端(我想是Votifier的Java版本)使用RSAES PKCS1 v1.5。使用该方案添加了一个解码方法，并更改了对该方法的调用:

在Main ():

decodedfile = decode_msg_v1_5(data, privatekey)

新方法:

def decode_msg_v1_5(ciphertext, privateKey):
    """  Should consider using the more robust PKCS1 OAEP. """
    sentinel = Random.new().read(256)      # data length is 256
    cipher = PKCS1_v1_5.new(privateKey)
    messagereceived = cipher.decrypt(ciphertext, sentinel)
    return messagereceived