>我有一个 sqlite 查询,它返回类似于以下内容的内容,其中包含列 [字母、数字]:
("a", 1)
("a", 2)
("b", 3)
("c", 3)
如果字母不同,我想将数字列检索为 0。 怎么做?
预期产出:
("a", 1)
("a", 2)
("b", 0)
("c", 0)
SELECT tba.mychar
-- if tbu.mychar is null, then the letter is not unique
-- when it happens, the letter is not "unique" thus use the number column
-- else use zero for "unique" letters
, CASE WHEN tbu.mychar IS NULL THEN tba.mynum ELSE 0 END AS newnum
FROM mytab tba
LEFT JOIN (
-- this subquery only returns the letters that don't repeat
SELECT mychar
FROM mytab
GROUP BY mychar
HAVING COUNT(*) = 1
) AS tbu ON tba.mychar=tbu.mychar
您可以使用子查询:
select t1.col1,
case when t2.cnt > 1 then t1.col2 else 0 end col2
from table1 t1
left join
(
select count(*) as cnt, col1
from table1
group by col1
) t2
on t1.col1 = t2.col1
请参阅带有演示的 SQL 小提琴
How how
how (SQL Fiddle):
SELECT Q.letter,
CASE WHEN (SELECT COUNT(*) FROM (query) QQ WHERE QQ.letter = Q.letter) = 1 THEN 0
ELSE Q.number
END AS number
FROM (query) Q
请注意,将"查询"替换为生成第一个结果的查询。
可以使用 UNION ALL 2 个单独的语句(一个用于重复的字母,一个用于只出现一次的字母)来执行此操作:
SELECT letter, number
FROM tableName
WHERE letter IN (
SELECT letter
FROM tableName
GROUP BY letter
HAVING COUNT(1) > 1
)
UNION ALL
SELECT letter, 0
FROM tableName
WHERE letter IN (
SELECT letter
FROM tableName
GROUP BY letter
HAVING COUNT(1) = 1
)