我想从导航堆栈中删除以前的视图控制器。
例如
-> A 是根视图。现在
导航到 B - B 导航到 C - C 导航到 C - C 导航到 C -->现在我想删除所有 C 视图控制器并弹出到 B
B 不是修复视图控制器。
另一个例子
A -> b -> c> g> c> f> c> c> c>c
从导航中删除所有c视图控制器并需要以下输出
A -> b -> c>g> c> f
请帮助我
从导航堆栈中识别控制器。并弹出到该控制器
NSArray *viewControllers = [[self navigationController] viewControllers];
int count = [viewControllers count];
for (int i= count-2; i >= 0 ; i--) {
id obj=[viewControllers objectAtIndex:i];
if(![obj isKindOfClass:[C class]]){
[[self navigationController] popToViewController:obj animated:YES];
return;
}
}
popToViewController
(https://developer.apple.com/documentation/uikit/uinavigationcontroller/1621871-poptoviewcontroller(。例:
在目标C中
[self.navigationController popToViewController:self.navigationController.viewControllers[your_VC_index] animated: true];
// in first eg your_VC_index will be 1 and another example it will be 5
在斯威夫特 3 中
self.navigationController.popToViewController( self.navigationController.viewControllers[your_VC_index], animated: true)
反向迭代导航堆栈并获取第一个不匹配的视图控制器的索引,然后获取popToViewController
if let controllers = self.navigationController?.viewControllers {
var count = controllers.count - 1
for viewcontroller in controllers.reversed() {
if viewcontroller is CViewController {
count -= 1
} else {
break
}
}
let vc = controllers[count]
self.navigationController?.popToViewController(vc, animated: true)
}
编写如下所示的方法,
- (void)removeAllLastCObjectsFromNavigationController {
//fetch viewcontroller array. for your case which will be A - > b -> c > g > c > f > c > c > c > c
NSArray *viewControllers = yourNavigationController.viewControllers;
NSMutableArray *mutableArray = [NSMutableArray arrayWithArray: viewControllers];
while(1) {
id viewController = mutableArray.lastObject;
if ([viewController isKindOfClass:[YourCClassName class]]) {
//Now continue removing the objects from the array if that is C type object.
[mutableArray removeLastObject];
} else {
//If found any other class than C stop removing viewcontroller
break;
}
}
//Now mutableArray contains A - > b -> c > g > c > f
yourNavigationController.viewControllers = mutableArray;
}
因为 navigationController 的 childViewController 是一个堆栈,
所以使用这个函数可以弹出到 f viewController 而 "c> c> c> c"被销毁。
for (UIViewController *tempVC in self.navigationController.childViewControllers) {
if ([tempVC isKindOfClass:[fViewController class]]) {
fViewController *f = (fViewController *)tempVC;
[self.navigationController popToViewController:f animated:YES];
}
}
但是,如果您不想弹出到 f,只想获取导航控制器的新子视图控制器。 您可以使用下一个函数:
for (UIViewController *tempVC in self.navigationController.childViewControllers) {
if ([tempVC isKindOfClass:[ScanViewController class]]) {
NSUInteger findex = [self.navigationController.childViewControllers indexOfObject:tempVC];
NSMutableArray *viewArray = [NSMutableArray arrayWithArray:self.navigationController.childViewControllers];
[viewArray removeObjectsInRange:NSMakeRange(findex, viewArray.count - 1)];
}
}
viewArray 是新的 childViewControllers。如果您有新的需求,可以编辑此函数然后使用它。