如何合并 Solr 嵌套文档中的父项和子项

Question

我是lucence，solr查询的新手，我对如何查询嵌套文档有疑问。

我已将嵌套文档索引，如下所示

[
{
"id": "1",
"title": "Solr1",
"_childDocuments_": [
{
"id": "2",
"title": "Solr2",
"_childDocuments_": [
{
"id": "3",
"title": "Solr3",
"_childDocuments_": [
{
"id": "4",
"title": "SolrCloud supports it"
}
],
"something_else":"irrelevant"
}
],
"something_else":"irrelevant"
}
],
"something_else":"irrelevant"
},
{
"id": "5",
"title": Solr5",
"_childDocuments_": [
{
"id": "6",
"title": "SolrCloud here as well"
}
]
}
]

如何搜索标题：SolrCloud，并列出所有孩子的父母？如

[
{
"id": "1",
"title": "Solr1",
"_childDocuments_": [
{
"id": "2",
"title": "Solr2",
"_childDocuments_": [
{
"id": "3",
"title": "Solr3",
"_childDocuments_": [
{
"id": "4",
"title": "SolrCloud supports it"
}
]
}
]
}
]
},
{
"id": "5",
"title": Solr5",
"_childDocuments_": [
{
"id": "6",
"title": "SolrCloud here as well"
}
]
}
]

其中列出了文档 4(Sorl1、Solr2、Solr3(和文档 6(Solr5(的所有父项。 文档的深度不是常量。

Answer 1

我目前的解决方案是按摩数据，将跟踪添加到原始数据中，这样我就会知道文档来自。

如

[
{
"id": "1",
"title": "Solr1",
"_childDocuments_": [
{
"id": "2",
"title": "Solr2",
**"parent_id":"1",**
**"trace":"Solr1",**
"_childDocuments_": [
{
"id": "3",
"title": "Solr3",
**"parent_id":"2",**
**"trace":"Solr1/Solr2",**
"_childDocuments_": [
{
"id": "4",
"title": "SolrCloud supports it"
**"parent_id":"3",**
**"trace":"Solr1/Solr2/Solr3",**
}
],
"something_else":"irrelevant"
}
],
"something_else":"irrelevant"
}
],
"something_else":"irrelevant"
},
{
"id": "5",
"title": Solr5",
"_childDocuments_": [
{
"id": "6",
**"parent_id":"5",**
**"trace":"Solr5",**
"title": "SolrCloud here as well"
}
]
}
]

因此，在索引之后，我可以从结果中知道谁是父文档。

有人可以同意这一点吗？ 寻找比这更好的解决方案。