我想要的是将手机号码发送到数据库并获取客户对象。我调试遵循代码,并看到返回NULL客户对象。有帮助吗?
public Customer unSuccessfulLoginAttempts(String mobileNumber) {
log.info("<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<| Unsuccessful Logging Attempts Repository Starting|>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> {}" ,mobileNumber );
Session session = entityManager.unwrap(Session.class);
Criteria criteria = session.createCriteria(Customer.class,"c");
Criterion mobile = Restrictions.eq("c.phone1",mobileNumber);
criteria.add(Restrictions.eq("u.phone1", mobileNumber));
return (Customer) criteria.list();
}
从我可以看到的别名是"c"
,但您正在使用"u"
。您需要:
List customer = session.createCriteria(Customer.class)
.add(Restrictions.eq("phone1", mobileNumber))
.list();
您的变量手机也未使用。