获取本地日期而不是 UTC

Question

以下脚本计算我下周五和下周日的日期。

问题：使用.toISOString使用UTC时间。我需要用输出本地时间的东西进行更改。我对javascript很陌生，所以我找不到合适的属性来代替.toIsostring。 我该怎么办？

function nextWeekdayDate(date, day_in_week) {
var ret = new Date(date || new Date());
ret.setDate(ret.getDate() + (day_in_week - 1 - ret.getDay() + 7) % 7 + 1);
return ret;
}
let nextFriday = nextWeekdayDate(null, 5);
let followingSunday = nextWeekdayDate(nextFriday, 0);
console.log('Next Friday     : ' + nextFriday.toDateString() +
'nFollowing Sunday: ' + followingSunday.toDateString());
/* Previous code calculates next friday and next sunday dates */
var checkinf = nextWeekdayDate(null, 5);
var [yyyy, mm, dd] = nextFriday.toISOString().split('T')[0].split('-');
var checkouts = nextWeekdayDate(null, 7);
var [cyyy, cm, cd] = followingSunday.toISOString().split('T')[0].split('-');

Answer 1

如果您担心某些时区的日期错误，请尝试规范化时间

要不使用 toISO，您可以这样做

const [dd1, mm1, yyyy1] = nextFriday.toLocaleString('en-GB', 
{ year: 'numeric', month: '2-digit', day: '2-digit' })
.split("/")

function nextWeekdayDate(date, day_in_week) {
var ret = new Date(date || new Date());
ret.setHours(15, 0, 0, 0); // normalise
ret.setDate(ret.getDate() + (day_in_week - 1 - ret.getDay() + 7) % 7 + 1);
return ret;
}
let nextFriday = nextWeekdayDate(null, 5);
let followingSunday = nextWeekdayDate(nextFriday, 0);
console.log('Next Friday     : ' + nextFriday.toDateString() +
'nFollowing Sunday: ' + followingSunday.toDateString());
/* Previous code calculates next friday and next sunday dates */
var checkinf = nextWeekdayDate(null, 5);
var [yyyy, mm, dd] = nextFriday.toISOString().split('T')[0].split('-');
var checkouts = nextWeekdayDate(null, 7);
var [cyyy, cm, cd] = followingSunday.toISOString().split('T')[0].split('-');
console.log(yyyy, mm, dd)
// not using UTC: 
const [dd1, mm1, yyyy1] = nextFriday.toLocaleString('en-GB', { year: 'numeric', month: '2-digit', day: '2-digit' }).split("/")
console.log(yyyy1, mm1, dd1)

Answer 2

您担心 [yyyy，mm，dd] 采用 UTC 而不是当前 timzone？

下一个星期五是一个日期对象。如果您改用 get 函数，它会起作用吗？ 例如

const nextFridayYear = nextFriday.getFullYear();
// get month is zero index based, i have added one
const nextFridayMonth = (nextFriday.getMonth() + 1).toString()
.padStart(2, '0');
const nextFridayDay = today.getDate().toString()
.padStart(2, '0');