如何使用从Scala到Python的AES加密和解密

Question

我有一个scala中的代码，其中有我的加密和解密代码，它运行良好，代码为：

import java.util.Base64
import javax.crypto.Cipher
import javax.crypto.spec.{IvParameterSpec, SecretKeySpec}
class Encryption {
val key = "enIntVecTest2020"
val initVector = "encryptionIntVec"
def encrypt(text: String): String = {
val  iv = new IvParameterSpec(initVector.getBytes("UTF-8"))
val  skeySpec = new SecretKeySpec(key.getBytes("UTF-8"), "AES")
val  cipher = Cipher.getInstance("AES/CBC/PKCS5PADDING")
cipher.init(Cipher.ENCRYPT_MODE, skeySpec, iv)
val  encrypted = cipher.doFinal(text.getBytes())
return Base64.getEncoder().encodeToString(encrypted)
}
def decrypt(text:String) :String={
val  iv = new IvParameterSpec(initVector.getBytes("UTF-8"))
val  skeySpec = new SecretKeySpec(key.getBytes("UTF-8"), "AES")
val  cipher = Cipher.getInstance("AES/CBC/PKCS5PADDING")
cipher.init(Cipher.DECRYPT_MODE, skeySpec, iv)
val  original = cipher.doFinal(Base64.getDecoder.decode(text))
new String(original)
}
}
val encryptobj = new Encryption()
val pwd = "#test@12345"
val result =encryptobj.encrypt(pwd)

pwd:String=#test@12345
结果：String=lHhq1OzMSYnj+0XxiNzKhQ==

val pwd1  = encryptobj.decrypt(result)
println(pwd1)

pwd1：字符串=#test@12345
#test@12345

我尝试在Python中实现同样的效果，但没有给出预期的加密结果，这是我的代码(我得到了其他类似答案的帮助(：

from hashlib import sha256
import base64
from Crypto import Random
from Crypto.Cipher import AES
BS = 16
pad = lambda s: bytes(s + (BS - len(s) % BS) * chr(BS - len(s) % BS), 'utf-8')
unpad = lambda s : s[0:-ord(s[-1:])]
class AESCipher:
def __init__( self, key ):
self.key = bytes(key, 'utf-8')
def encrypt( self, raw ):
raw = pad(raw)
iv = "encryptionIntVec".encode('utf-8')
cipher = AES.new(self.key, AES.MODE_CBC, iv )
return base64.b64encode( iv + cipher.encrypt( raw ) )
def decrypt( self, enc ):
enc = base64.b64decode(enc)
iv = enc[:16]
cipher = AES.new(self.key, AES.MODE_CBC, iv )
return unpad(cipher.decrypt( enc[16:] )).decode('utf8')
cipher = AESCipher('enIntVecTest2020')
encrypted = cipher.encrypt('#test@12345')
decrypted = cipher.decrypt(encrypted)

print(encrypted)

b'ZW5jcnlwdGlvbkludFZlY5R4tTszEmJ4/tF8YjcyoU='

正如你所看到的，加密都是不对的，我不知道我哪里做错了。请帮助在python中实现与scala中相同的加密结果，我将非常感谢。

Answer 1

感谢@Topaco的回答，经过一番搜索，它成功了。

import base64
from Crypto.Cipher import AES
BS = 16
pad = lambda s: bytes(s + (BS - len(s) % BS) * chr(BS - len(s) % BS), 'utf-8')
unpad = lambda s : s[0:-ord(s[-1:])]
class AESCipher:
def __init__( self, key ):
self.key = bytes(key, 'utf-8')
def encrypt( self, raw ):
raw = pad(raw)
iv = "encryptionIntVec".encode('utf-8')
cipher = AES.new(self.key, AES.MODE_CBC, iv )
return base64.b64encode(cipher.encrypt( raw ) )
def decrypt( self, enc ):
iv = "encryptionIntVec".encode('utf-8')
enc = base64.b64decode(enc)
cipher = AES.new(self.key, AES.MODE_CBC, iv )
return unpad(cipher.decrypt( enc )).decode('utf8')
cipher = AESCipher('enIntVecTest2020')
encrypted = cipher.encrypt('#test@12345')
print(encrypted.decode('utf-8'))
-> lHhq1OzMSYnj+0XxiNzKhQ==
decrypted = cipher.decrypt(encrypted)
print(decrypted)
-> #test@12345