如何使运行函数的UIImages可点击?(斯威夫特)

Question

（我几天前刚开始使用Swift，对编程还比较陌生，所以请耐心等待。）我正在尝试让随机块出现在屏幕上，用户必须点击它们才能让它们消失。我已经能够创建这些块，但我不知道如何真正使它们可点击。有人能帮帮我吗？这是我迄今为止的代码：

func createBlock(){
    let imageName = "block.png"
    let image = UIImage(named: imageName)
    let imageView = UIImageView(image: image!)
    imageView.frame = CGRect(x: xPosition, y: -50, width: size, height: size)
    self.view.addSubview(imageView)
    UIView.animateWithDuration(duration, delay: delay, options: options, animations: {
        imageView.backgroundColor = UIColor.redColor()
        imageView.frame = CGRect(x: self.xPosition, y: 590, width: self.size, height: self.size)
        }, completion: { animationFinished in

            imageView.removeFromSuperview()
            self.life-=1

    })

}

我想让方块在敲击时消失；关于我该怎么做有什么建议吗？

Answer 1

这非常简单，只需使用UIMapGestureRecognizer即可。我通常将识别器初始化为全局变量。

let tapRecognizer = UITapGestureRecognizer()

然后在您的视图中DidLoad:

// Replace with your function
tapRecognizer.addTarget(self, action: "removeBlock")
imageView.addGestureRecognizer(tapRecognizer)

Answer 2

func removeImage(gesture: UIGestureRecognizer) {
    gesture.view?.removeFromSuperview()
}
func createBlock() {
    let imageName = "block.png"
    let image = UIImage(named: imageName)
    let imageView = UIImageView(image: image!)
    imageView.frame = CGRect(x: xPosition, y: -50, width: size, height: size)
    imageView.userInteractionEnabled = true                       // IMPORTANT
    imageView.addGestureRecognizer(UITapGestureRecognizer(target: self, action: "removeImage:"))
    self.view.addSubview(imageView)
    UIView.animateWithDuration(duration, delay: delay, options: options, animations: {
        imageView.backgroundColor = UIColor.redColor()
        imageView.frame = CGRect(x: self.xPosition, y: 590, width: self.size, height: self.size)
    }, { _ in
        imageView.removeFromSuperview()
        self.life-=1
    })
}

注意imageView.userInteractionEnabled = true，它非常重要，因为这将允许在该视图上发生触摸事件，在UIImgageView中，它被设置为false作为defaul。