在执行strcpy时获取分割故障错误

Question

每当我尝试执行字符串副本时，就会获取分割错误。但是，当我要进行直接分配时，相同的代码将起作用。在if语句中，我正在执行strcpy操作，从而获得内存损坏问题。帮助我了解此代码的" strcpy"功能。

 int getEnvVariable()
{
   char mPath[20];
   char mHome[20];
   char *AddressHolder[2];
   char *VariableName[2];
   VariableName[0]="PATH";
   VariableName[1]="HOME";
   memset(&mPath,sizeof(mPath),0);
   memset(&mHome,sizeof(mHome),0);
   AddressHolder[0]=reinterpret_cast<char*>(&mPath);
   AddressHolder[1]=reinterpret_cast<char*>(&mHome);
  char** namePtr = VariableName;
  char** vrbPtr = AddressHolder;
  char* tmp;
  while(*namePtr != NULL)
  {
    tmp = getenv(*namePtr);
    cout<<"n tmp - "<<tmp<<"n";
    if(tmp)
    {
      strcpy(*vrbPtr,tmp);
      //*vrbPtr=tmp;
      cout<<"n"<<*namePtr<<": "<<*vrbPtr;
      ++namePtr;
      ++vrbPtr;
    }
    else
    {
       cout<<"n Error: Environment veribale name are not setn";
       return -1;
    }
  }
   cout<<"n"<<VariableName[0]<<" : "<<mPath;
   cout<<"n"<<VariableName[1]<<" : "<<mHome;
   return 0;
}

Answer 1

在strcpy中， *vrbptr指向了请客的地址。您想指向无环持有人[0]