我有以下代码将日期转换为毫秒:
long lond dateToMs(const char* text)
{
std::tm tm = {};
const char* snext = ::strptime(text, "%d-%m-%Y %H:%M:%S", &tm);
auto time_point = std::chrono::system_clock::from_time_t(std::mktime(&tm));
return time_point.time_since_epoch() / std::chrono::milliseconds(1) + std::atof(snext) * 1000.0f;
}
当我有一个不存在的日期时 例如:40-10-2015 12:23:45.2354
程序显示以下消息: Segmentation fault (core dumped)
相反,我想显示类似 The introduced date it's not valid
.我试过了..捕获块如下:
long long dateToMs(const char* text)
{
try{
std::tm tm = {};
const char* snext = ::strptime(text, "%d-%m-%Y %H:%M:%S", &tm);
auto time_point = std::chrono::system_clock::from_time_t(std::mktime(&tm));
return time_point.time_since_epoch()/std::chrono::milliseconds(1)+std::atof(snext)*1000.0f;
}
catch(const std::exception &)
{
std::cout << "The introduced date it's not valid" << std::endl;
};
}
但它显示了相同的错误:Segmentation fault (core dumped)
,我必须做什么才能显示我想要的消息错误。
您没有考虑snext
为空的可能性。
long long dateToMs(const char* text)
{
std::tm tm = {};
const char* snext = ::strptime(text, "%d-%m-%Y %H:%M:%S", &tm);
if ( snext )
{
auto time_point = std::chrono::system_clock::from_time_t(std::mktime(&tm));
return time_point.time_since_epoch() / std::chrono::milliseconds(1) + std::atof(snext) * 1000.0f;
}
else
{
std::cout << "The introduced date it's not valid";
}
}
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