宾果游戏爪哇

Question

我正在尝试编写Java代码(宾果游戏(，(靶心游戏( 规则很简单：

• 电脑选4个号码

• 用户输入 4 个数字

• 必须检查用户输入是否在 1 到 10 之间

• 如果用户输入存在于计算机随机数中，它将是 1 公牛

• 如果一个数字存在于计算机随机数的同一位置，它将显示 1 只"眼睛">

最大限制为 20 次尝试，直到用户被视为"失败";我需要根据用户输入打印每一轮有多少公牛和多少只眼睛;

例：

if the pc randomizing 1 4 6 7
and the user type 3 4 1 7 
the output will be 3 bulls and 2 eyes.

我的代码在末尾打印 0 和 0。

感谢您的帮助！

这是我的代码：

import java.util.Random;
import java.util.Scanner;
public class ArraysEx1 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
Random r = new Random();
int[] pcGuess = new int[4];
int[] playerGuess = new int[4];
int countGuess = 0, bulls = 0, eye = 0;
final int maxGuess = 20;
System.out.println("Please press enter to begin");
in.nextLine();
boolean areNumbersCorrect = true; // a boolean value to define if the user input are correct (values between 1 to 10)
for (; countGuess < maxGuess; countGuess++) {
System.out.println("Please enter 4 numbers between 1-10");
for (int i = 0; i < playerGuess.length; i++) {
playerGuess[i] = in.nextInt();
pcGuess[i] = r.nextInt(10)+1;
if (playerGuess[i] < 0 || playerGuess[i] > 10) { // an if statement to check if the user input are correct
areNumbersCorrect = false;
do {                                            // do while loop if the boolean is not true. (force the user to enter correct values)
System.out.println("Please try again");
for (int j = 0; j < playerGuess.length; j++) {
playerGuess[j] = in.nextInt();
if (playerGuess[j] > 0 && playerGuess[j] < 10) {
areNumbersCorrect = true;
continue;
}
}
} while (!areNumbersCorrect); // end of do while loop
}
for (int j=pcGuess.length; j>0; j--) { // for loop to check each number from the user and computer.
if (playerGuess[i] == pcGuess[i]) {
eye++;                             // if the user number exist in the same location evaluate eye++
if (playerGuess[i]%pcGuess[j]== 0) {
bulls++;                        // if the user number exist in the randomized number but not in the same location evaluate bulls++
}
}
}
System.out.println(
eye+" Hits!(same pc number and location)"+" And: "+bulls+" Numbers exist");
} if(eye==4&&bulls==4) {
break;
}
}
System.out.println("It took you: "+countGuess+" Times to guess the numbers");
}
}

Answer 1

import java.util.ArrayList;
import java.util.Random;
import java.util.Scanner;
public class ArraysEx1 {
public static void main(String[] args) {
ArrayList<Integer> randNumbers = new ArrayList<>();
Random random = new Random();
String input;
int number;
Scanner sc = new Scanner(System.in);
do {
System.out.println("Please press enter to begin");
input = sc.nextLine();
}while (!input.equals(""));//loop while user doesn't press ENTER
for (int i = 0; i < 4; i++){
randNumbers.add(random.nextInt(10) + 1);//loop to fill the randNumbers arraylist with random numbers
}
/*
randNumbers.add(3);
randNumbers.add(2);
randNumbers.add(9);
randNumbers.add(9);
*/
System.out.println("My random numbers: " + randNumbers.toString());
int counter = 0;
int bulls = 0;
int eyes = 0;
do {
System.out.println("Please enter 4 numbers between 1-10");
number = sc.nextInt();
if (number > 0 && number <= 10){
//System.out.println("index of rand: " + randNumbers.indexOf(number));
//System.out.println("count: " + counter);
if (randNumbers.indexOf(number) == counter){
eyes++;
System.out.println("eyes++");
}else if (randNumbers.contains(number)){
bulls++;
System.out.println("bulls++");
}
counter++;
System.out.println("Number " + counter + " introduced. " + (4 - counter) + " more to go.");
}else {
System.out.println("Wrong number.");
}
}while (counter < 4);//loop for user to introduce valid numbers
System.out.println("You scored " + bulls + " bulls and " + eyes + " eyes.");
}
}

试试这段代码。请注意，我使用的是 ArrayList 而不是数组，因为它提供了 .contains(( 和 .indexof(( 等方法。

警告：如果 randNumbers 数组列表包含两个相等的数字，例如当您输入 9-9-9-9 作为数字猜测时注释的 3-2-9-9 数组，代码将失败。这是因为 .indexof(( 方法：

返回指定元素第一次出现的索引 在此列表中，如果此列表不包含该元素，则为 -1。

这意味着代码无法解释最后 9，因为它会将计数索引 (3( 与 randNumbers 中第一次出现的 9(即 2(进行比较，使其为假并且不会增加眼睛计数。

由于我时间不多，而且这是你的一个习惯，只是复制它不会教你太多，我会把它留给你来解决这个具体案例(我已经告诉你出了什么问题，不会很难解决(。