使用Abaqus Python创建一个带有草图的表面

Question

我的问题听起来很简单，但我在Abaqus脚本编写方面的知识几乎不存在。我的目标是在同一零件中表示一组多边形，其中每个多边形表示零件的2D表面(在3D空间中)。我正在创建一个脚本来生成每个多边形的草图(不确定这是否是最好的方法)。然后为每个草图创建一个表面。

我怎样才能做到这一点?

多谢!

代码:

from abaqus import *
from abaqusConstants import *
import sketch
import part
MyModel=mdb.Model(name='Model-1')

#-------------FIRST POLYGON------------------------------- 
s1=MyModel.ConstrainedSketch(name='__poly0__', sheetSize=100)
g, v, d, c = s1.geometry, s1.vertices, s1.dimensions, s1.constraints
s1.Line(point1=(10.0, 10.0), point2=(10.0, 15.0))
s1.Line(point1=(10.0, 15.0), point2=(-10.0, 15.0))
s1.Line(point1=(-10.0, 15.0), point2=(-10.0, -15.0))
s1.Line(point1=(-10.0, -15.0), point2=(10.0, -15.0))
s1.Line(point1=(10.0, -15.0), point2=(10.0, -10.0))
s1.Line(point1=(10.0, -10.0), point2=(5, 0))
s1.Line(point1=(5, 0), point2=(10.0, 10.0))
#-------------SECOND POLYGON-------------------------------
s2=MyModel.ConstrainedSketch(name='__poly1__', sheetSize=100)
g, v, d, c = s2.geometry, s2.vertices, s2.dimensions, s2.constraints
s2.Line(point1=(10.0, 10.0), point2=(5, 0))
s2.Line(point1=(5, 0), point2=(10.0, -10.0))
s2.Line(point1=(10.0, -10.0), point2=(10.0, -15.0))
s2.Line(point1=(10.0, -15.0), point2=(15.0, -15.0))
s2.Line(point1=(15.0, -15.0), point2=(15.0, 0.0))
s2.Line(point1=(15.0, 0.0), point2=(10, 10))
#----------ONE PART WITH TWO PLANAR FACES (ONE PER POLYGON)-----
p = mdb.models['Model-1'].Part(name='Part-1', dimensionality=THREE_D,type=DEFORMABLE_BODY)
p = mdb.models['Model-1'].parts['Part-1']
#How can I put two planar faces here?
#First Polygon
#p.BaseShell(sketch=s1)
#del mdb.models['Model-1'].sketches['__poly0__']
#Second Polygon
#p.BaseShell(sketch=s2)
#del mdb.models['Model-1'].sketches['__poly1__']
#-------------------------------------------------------------

Answer 1

Surface有两种含义。通常在Abaqus术语中，SURFACE是对零件或组件的面或边缘的引用。它通常不是指平坦的部分。在Abaqus之外，创建一个曲面可以理解为创建一个平面部件。

这是一个类似于你的代码，使零件在3D空间(2D零件将只具有Abaqus曲面意义上的边)。然后在两个面之一上创建Abaqus SURFACE。

from abaqus import *
from abaqusConstants import *
s1 = mdb.models['Model-1'].ConstrainedSketch(name='__profile__',sheetSize=200.0)
g, v, d, c = s1.geometry, s1.vertices, s1.dimensions, s1.constraints
s1.Line(point1=(-21.25, 22.5), point2=(-33.75, -20.0))
s1.Line(point1=(-33.75, -20.0), point2=(-3.75, -32.5))
s1.Line(point1=(-3.75, -32.5), point2=(40.0, -25.0))
s1.Line(point1=(40.0, -25.0), point2=(25.0, 25.0))
s1.Line(point1=(25.0, 25.0), point2=(-21.25, 22.5))
#this creates the actual part - which is a planar surface that exists in 3D space
p = mdb.models['Model-1'].Part(name='Part-2', dimensionality=THREE_D,type=DEFORMABLE_BODY)
p = mdb.models['Model-1'].parts['Part-2']
p.BaseShell(sketch=s1)
del mdb.models['Model-1'].sketches['__profile__']

#the following finds and creates a "surface" on the part. 
f = p.faces
face=f.findAt(coordinates=(0.0,0.0,0.0))
face_ind=face.index
side1Faces=f[face_ind:face_ind+1]
p.Surface(side1Faces=side1Faces, name='Surf-1')

如果这不是你的问题所问的，请在你的问题中解释更多。