Android HttpUrlConnection不能Post -错误403

Question

我正在尝试使用spring安全csrf对我的web服务发出HttpPost。

首先，我试图通过GET请求恢复XSRF TOKEN，如下所示

public static CookieManager xcsrfToken() throws IOException{
    String token;
    URL url = new URL(urlBase);
    HttpURLConnection con = (HttpURLConnection) url.openConnection();
    con.setRequestMethod("GET");
    CookieManager cookieManager = new CookieManager();
    con.connect();
    List<String> cookieHeader = con.getHeaderFields().get("Set-Cookie");
    if (cookieHeader != null) {
        for (String cookie : cookieHeader) {
            cookieManager.getCookieStore().add(null, HttpCookie.parse(cookie).get(0));
        }
    }
    System.out.println(con.getHeaderFields());
    con.disconnect();
    return cookieManager;
}

这是我从con.getHeaderFields()

得到的结果

{null=[HTTP/1.1 200 OK], Cache-Control=[no-cache, no-store, max-age=0, must-revalidate], Content-Language=[pt-BR], Content-Length=[973], Content-Type=[text/html;charset=ISO-8859-1], Date=[Wed, 19 Aug 2015 10:40:18 GMT], Expires=[0], Pragma=[no-cache], Server=[Apache-Coyote/1.1], Set-Cookie=[JSESSIONID=6C9326FBEEA14752068720006F2B5EAA; Path=/webapi/; HttpOnly, XSRF-TOKEN=07cbed7f-834e-4146-8537-0a6b5669f223; Path=/], X-Android-Received-Millis=[1439980819720], X-Android-Response-Source=[NETWORK 200], X-Android-Sent-Millis=[1439980819693], X-Content-Type-Options=[nosniff], X-Frame-Options=[DENY], X-XSS-Protection=[1; mode=block]}

XSRF-TOKEN在我的cookie中，ok!如果我用.getCookies System.out.println (cookieManager.getCookieStore () ());我得到了这个

[JSESSIONID=5B1D3E2D3E7B3E1E6572A3839BFF3741, XSRF-TOKEN=4d4048bd-f21c-48c6-895e-5f67523ad963]

现在，我试图向服务器发出POST，像这样

public static HttpURLConnection makeRequest(String metodo, String uri, String requestBody) throws IOException{
    URL url = new URL(urlBase + uri);
    HttpURLConnection con = (HttpURLConnection) url.openConnection();
    con.setRequestMethod("POST");
    con.setDoInput(true);
    con.setDoOutput(!metodo.equals("GET"));
    con.setRequestProperty("Content-Type", "application/json");
    con.setRequestProperty("Cookie", TextUtils.join("," , xcsrfToken().getCookieStore().getCookies()));
    con.connect();
    InputStream is = con.getErrorStream();
    System.out.println(IOUtils.toString(is, "UTF-8"));
    System.out.println(con.getHeaderFields());
    return con;
}

但是报头返回时没有cookies

 {null=[HTTP/1.1 403 Forbidden], Cache-Control=[no-cache, no-store, max-age=0, must-revalidate], Content-Language=[en], Content-Length=[1149], Content-Type=[text/html;charset=utf-8], Date=[Wed, 19 Aug 2015 10:42:18 GMT], Expires=[0], Pragma=[no-cache], Server=[Apache-Coyote/1.1], X-Android-Received-Millis=[1439980939827], X-Android-Response-Source=[NETWORK 403], X-Android-Sent-Millis=[1439980939811], X-Content-Type-Options=[nosniff], X-Frame-Options=[DENY], X-XSS-Protection=[1; mode=block]}

它说没有CSRF有效令牌

Invalid CSRF Token 'null' was found on the request parameter '_csrf' or header 'X-XSRF-TOKEN'.

在我的webservice中，令牌被配置为重命名为XSRF-TOKEN，因为angularJs。

<<p> 解决方案/strong>

public static void getTokens() throws IOException{
    URL url = new URL(urlBase);
    HttpURLConnection con = (HttpURLConnection) url.openConnection();
    con.setRequestMethod("GET");
    con.connect();
    cookieManager = new CookieManager();
    List<String> cookieHeader = con.getHeaderFields().get("Set-Cookie");
    if (cookieHeader != null) {
        for (String cookie : cookieHeader) {
            String[] tokens = TextUtils.split(cookie, "=");
            if (tokens[0].equals("JSESSIONID"))
                cookieManager.getCookieStore().add(null, HttpCookie.parse(cookie).get(0));
            if (tokens[0].equals("XSRF-TOKEN")) {
                String[] tokenValue = TextUtils.split(tokens[1],";");
                xsrfTOKEN = tokenValue[0];
            }
        }
    }
    con.disconnect();
}

然后，将它附加到HttpUrlConnection

con.setRequestProperty("X-XSRF-TOKEN", xsrfTOKEN);

Answer 1

根据我的经验，我们需要将令牌作为请求头提交。Spring默认希望它的名称为X-CSRF-TOKEN。但是使用AngularJS的人通常会在Spring Security配置中将其更改为X-XSRF-TOKEN。

但是看看你的代码，我不知道你是否在发送那个头信息。

如果有帮助的话，下面是我的一个项目的一个片段(使用RestAssured):

if (xsrfToken != null && !ctx.getRequestMethod().equals(Method.GET))
    requestSpec.header("X-XSRF-TOKEN", xsrfToken);