cURL中的数据二进制参数

Question

我必须通过php中的cURL发送数据二进制参数
这是命令：curl -D - -u user:password -X PUT -H "Content-Type: text/plain" --data-binary "data-id=2010-10-01_15-15-53" https://someurl。在控制台中，这是可行的，现在我必须在php中完成。

这是我的代码：

    $this->_curl = curl_init();
    curl_setopt($this->_curl, CURLOPT_USERPWD, $this->_loginUser . ":" . $this->_loginPassword);
    curl_setopt($this->_curl, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($this->_curl, CURLOPT_HEADER, 1);
    curl_setopt($this->_curl, CURLOPT_FOLLOWLOCATION, 1);
    curl_setopt($this->_curl, CURLOPT_TIMEOUT, 30);
    curl_setopt($this->_curl, CURLOPT_URL, $this->_serviceUrl);//https://someurl
    curl_setopt($this->_curl, CURLOPT_HTTPHEADER, array('Content-Type: text/plain'));
    curl_setopt($this->_curl, CURLOPT_CUSTOMREQUEST, 'PUT');
    curl_setopt($this->_curl, CURLOPT_POSTFIELDS, array('data-id' => $dataId));//d'2010-10-01_15-15-53'
    $response = curl_exec($this->_curl);
    //$response = HTTP/1.1 201 Created
    curl_close($this->_curl);

服务器接受了调用，但无法识别数据id参数：

触发器2010-10-01_15-15-53 中未定义数据id属性

知道我错过了什么吗？

Answer 1

您需要先将字符串转换为流。

您可以简单地使用这段代码来完成它。

$YourString = 'data-id=2010-10-01_15-15-53';
$stream = fopen('php://memory','r+');
fwrite($stream, $YourString );
$dataLength = ftell($stream);
rewind($stream);

然后有了你的流，你可以用curl发送它。

$curl = curl_init();
curl_setopt_array( $curl,
        array( CURLOPT_CUSTOMREQUEST => 'PUT'
        , CURLOPT_URL => 'https://someurl'
        , CURLOPT_HTTPHEADER => array(
            'Content-Type: text/plain'
        )
        , CURLOPT_RETURNTRANSFER => 1                     // means output will be a return value from curl_exec() instead of simply echoed
        , CURLOPT_TIMEOUT => 15                           // max seconds to wait
        , CURLOPT_FOLLOWLOCATION => 0                     // don't follow any Location headers, use only the CURLOPT_URL, this is for security
        , CURLOPT_FAILONERROR => 0                        // do not fail verbosely fi the http_code is an error, this is for security
        , CURLOPT_SSL_VERIFYPEER => 1                     // do verify the SSL of CURLOPT_URL, this is for security
        , CURLOPT_VERBOSE => 0                            // don't output verbosely to stderr, this is for security
        , CURLOPT_INFILE => $stream
        , CURLOPT_INFILESIZE => $dataLength
        , CURLOPT_UPLOAD => 1
        ) );
$response = curl_exec($curl);
$http_code = curl_getinfo($curl, CURLINFO_HTTP_CODE);
curl_close($curl);
echo($response.'<br/>');
echo($http_code.'<br/>');

这应该行得通。下面突出显示了对您有帮助的行：

CURLOPT_INFILE=>$stream

CURLOPT_INFILESIZE=>$dataLength

CURLOPT_UPLOAD=>1

Answer 2

为什么要将纯文本传递为二进制？

--data-binary "data-id=2010-10-01_15-15-53"

在这一行中，你说你想要传输纯文本，而不是二进制：

curl_setopt($this->_curl, CURLOPT_HTTPHEADER, array('Content-Type: text/plain'));

---

无论如何，我认为您的主要问题是使用PUT方法。(https://stackoverflow.com/a/8054241/333061)

我建议你以这种方式使用POST方法：

curl_setopt($this->_curl, CURLOPT_HTTPHEADER, array(
    'Accept: */*',
    'Connection: Keep-Alive',
    // this allows you transfer binary data through POST
    'Content-type: multipart/form-data'
    ));
curl_setopt($this->_curl, CURLOPT_POST, 1);
curl_setopt($this->_curl, CURLOPT_POSTFIELDS, 
    http_build_query(array('data-id' => $dataId)));

要通过curl/php轻松传输二进制数据，请检查以下内容：https://stackoverflow.com/a/3086357/333061