学习 ruby，这些代码片段是什么意思

Question

def winner(p1, p2)
  wins = {rock: :scissors, scissors: :paper, paper: :rock}
  {true => p1, false => p2}[wins[p1] == p2]
end

从这个问题：硬件不可能？："在不使用条件的情况下用红宝石创建一个石头剪刀布程序"

Answer 1

我承认，对于新手程序员来说，这不是最易读的代码。我重写了它，提取了一些变量并添加了注释。希望你现在能更好地理解它。

def winner(p1, p2)
  # rules of dominance, who wins over who
  wins = {
    rock: :scissors, 
    scissors: :paper, 
    paper: :rock
  }
  # this hash is here to bypass restriction on using conditional operators
  # without it, the code would probably look like 
  #   if condition
  #     p1
  #   else
  #     p2
  #   end
  answers = {
    true => p1, 
    false => p2
  }
  # given the choice of first player, which element can he beat?
  element_dominated_by_first_player = wins[p1]
  # did the second player select the element that first player can beat?
  did_player_one_win = element_dominated_by_first_player == p2
  # pick a winner from our answers hash
  answers[did_player_one_win]
end
winner(:rock, :scissors) # => :rock
winner(:rock, :paper) # => :paper
winner(:scissors, :paper) # => :scissors

Answer 2

如您所见，这是一个石头剪刀纸游戏。def 关键字启动方法定义。end意味着方法的结束。

方法正文的第一行wins = {rock: :scissors, scissors: :paper, paper: :rock}定义一个名为 wins 的哈希。这是红宝石中的语法糖。您也可以将此行写入wins = { :rock => :scissors, :scissors => :paper, :paper => :rock} .

以:开头的名称在红宝石中称为符号。符号对象表示 Ruby 解释器中的常量名称和一些字符串。

第 2 行{true => p1, false => p2}的第一部分也是一个哈希。并且wins[p1] == p2的值可以根据第一行计算。例如，如果使用 winner(:paper, :rock) 调用此方法，则wins[p1]现在:rock，wins[p1] == p2应true。所以{true => p1, false => p2}[true] p1.

ruby 中方法的返回值是最后一个表达式的值。