我正在尝试发送需要看起来像这样的API请求:
https://api.gibbly.com/1/device?format=json&Amp; ambody = {" selection" = {" selectionType":"注册"," selectionMatch":"," Incl.ederuntime":true}}
但是,当我使用下面的代码时,会出现错误。在响应的[结果]段中,我得到以下内容:
[RESULT] FAILURE: responseSerializationFailed(reason: Alamofire.AFError.ResponseSerializationFailureReason.jsonSerializationFailed(error: Error Domain=NSCocoaErrorDomain Code=3840 "Invalid value around character 0." UserInfo={NSDebugDescription=Invalid value around character 0.}))
我已经尝试了使用Postman的请求,并且效果很好,因此我认为问题是由代码引起的。
基于代码中的第一个"打印"语句,HTTP主体似乎正确:
Optional({"selection":{"selectionType":"registered","selectionMatch":"","includeSettings":true}})
我唯一能想到的是,Alamofire不会在请求中添加"格式= JSON& body =",但我不知道如何看待这种情况。任何帮助将不胜感激。
let headers: HTTPHeaders = [
"Authorization": "Bearer adsf023494axadf32342",
"Content-Type": "text/json"
]
let parameters: [String: Any] = [
"selection":[
"selectionType":"registered",
"selectionMatch":"",
"includeSettings":true
]
]
Alamofire.request(url!, method: .get, parameters: parameters, encoding: JSONEncoding.default, headers: headers).responseJSON {
response in
print(NSString(data: (response.request?.httpBody)!, encoding: String.Encoding.utf8.rawValue))
print(response)
}
用于获取方法使用urlencoding.default而不是jsonencoding.default.default in Alamofire请求
确定弄清楚。我做了以下操作:(1)将参数创建为字符串,(2)百分比编码它们,以便所有字符都可以用作URL,(3)将编码的参数添加到基本URL中,并且(4)使用了(4)带有基本URL的新URL,然后编码参数作为我的请求的URL。
let url = "https://api.gibbly.com/1/device?format=json&body="
let urlParams = "{"selection":{"selectionType":"registered","selectionMatch":"","includeSettings":true}}"
let urlEncoded = url + urlParams.addingPercentEncoding(withAllowedCharacters: .urlHostAllowed)!
let headerList : HTTPHeaders = [
"Authorization" : "Bearer " + (KeychainWrapper.standard.string(forKey: "accessToken"))!,
"Content-Type" : "text/json"
]
Alamofire.request(urlEncoded, method: .get, headers: headerList).responseJSON{
response in
print(response)
}