我在项目中正在研究yii2
,我有用户及其角色。每个角色都可以访问模块和子菜单。有一个名为SIM List
的子菜单,其中所有SIM
记录都可以查看。有一个名为issued_to
的字段,它告诉我们向哪个用户发出了哪些SIM卡。
除非向任何用户发出SIM,否则issued_to
字段将保持空。发出后,用户的名称将出现在SIM List
上。
现在,我想以一种只有特定用户才能看到列表的方式进行管理。例如,5 Sims
已发出给名为U
的用户。现在,用户U
只能看到发给他的SIM卡记录,否则列表应为空。
在我的Index
控制器中,我正在获取issued_to
字段名称,该字段名称默认为空。
public function actionIndex()
{
$searchModel = new SimsSearch();
$dataProvider = $searchModel->search(Yii::$app->request->queryParams);
return $this->render('index', [
'searchModel' => $searchModel,
'dataProvider' => $dataProvider,
]);
}
通过像下面这样做,我可以获得issued_to
用户ID
$model = $dataProvider->getModels()[0];
$user_id = $model['issued_to'];
var_dump($user_id);
exit();
现在,在此控制器中,我想添加一张user_id
的检查,该检查仅给我为该特定用户的记录。
索引视图
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
['class' => 'yiigridSerialColumn'],
//'id',
'imsi',
'sim_number',
'operator_name',
'data_details',
'sms_details',
'monthly_bill',
//'created_by',
[
'label' => 'Created By',
'value' => function ($data) {
if (is_object($data))
return $data->created->name;
return ' - ';
},
//'filter' => Html::activeDropDownList($searchModel, 'created_by', appmodelsUser::toArrayList(), ['prompt' => "Created By", 'class' => 'form-control']),
],
'created_at',
// 'updated_at',
'status',
// 'updated_by',
//'sim_stauts',
[
'label'=>'SIM Status',
'value'=>function($a){
return $a->getStatusvalue();
}
],
//'issued_to',
[
'label' => 'Issued To',
'value' => function ($d) {
if(is_object($d->user))
//return $d->user->name;
return $d->issued_to == '' ? '' : $d->user->username;
return ' - ';
// return $d->user->name;
},
'filter' => Html::activeDropDownList($searchModel, 'issued_to', appmodelsUser::toArrayList(), ['prompt' => "Users", 'class' => 'form-control']),
],
//'returned_by',
[
'label' => 'Returned By',
'value' => function ($d) {
if(is_object($d->user2))
//return $d->user->name;
return $d->returned_by == '' ? '' : $d->user->username;
return ' - ';
// return $d->user->name;
},
'filter' => Html::activeDropDownList($searchModel, 'returned_by', appmodelsUser::toArrayList(), ['prompt' => "Users", 'class' => 'form-control']),
],
'historic',
['class' => 'yiigridActionColumn'],
],
]); ?>
更新1
我的 search model
在
public function search($params)
{
$query = Sims::find();
// add conditions that should always apply here
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$this->load($params);
if (!$this->validate()) {
// uncomment the following line if you do not want to return any records when validation fails
// $query->where('0=1');
return $dataProvider;
}
// grid filtering conditions
$query->andFilterWhere([
'id' => $this->id,
'created_by' => $this->created_by,
'created_at' => $this->created_at,
'updated_at' => $this->updated_at,
'updated_by' => $this->updated_by,
'sim_stauts' => $this->sim_stauts,
'issued_to' => $this->issued_to,
'returned_by' => $this->returned_by,
'historic' => $this->historic,
]);
$query->andFilterWhere(['like', 'imsi', $this->imsi])
->andFilterWhere(['like', 'sim_number', $this->sim_number])
->andFilterWhere(['like', 'operator_name', $this->operator_name])
->andFilterWhere(['like', 'data_details', $this->data_details])
->andFilterWhere(['like', 'sms_details', $this->sms_details])
->andFilterWhere(['like', 'monthly_bill', $this->monthly_bill])
->andFilterWhere(['like', 'status', $this->status]);
return $dataProvider;
}
我该如何实现?任何帮助都将不胜感激。
根据您的描述,您的user_id
保存在issued_to
字段中,您只需要获取将当前记录的结果保存在user_id
中的结果issued_to
。
我假设您在网格视图中仅可登录用户可以看到您的搜索。
您应该先从request
对象Yii::$app->request->queryParams;
获取queryParams
数组,该数组的阵列的格式与POST
具有I.e ['ModelName']['field_name']
,因此您需要Infort issued_to
设置CC_25AS
$arrayParams['SimSearch']['issued_to']=Yii:$app->user->id;
您的actionIndex
应该像下面的
public function actionIndex()
{
$searchModel = new SimsSearch();
$queryParams=Yii::$app->request->queryParams;
//check if user or one of the managers
$isAdmin=in_array(Yii::$app->user->identity->user_role,[1,6]);
//set params if normal user
if(!$isAdmin){
$queryParams['SimsSearch']['issued_to']=Yii::$app->user->id;
}
$dataProvider = $searchModel->search($queryParams);
return $this->render('index', [
'searchModel' => $searchModel,
'dataProvider' => $dataProvider,
]);
}
希望这对您有帮助。