部署 Firebase 函数时出错:每个 then() 应该返回一个值或抛出 promise/always-return

Question

我已经尝试了类似帖子中推荐的常见解决方案，例如返回 null 或重新调整非 null 值，但这只会导致另一个部署错误，如下所示：

无法配置触发器提供程序/cloud.firestore/eventTypes/[e-mail]....

我也在使用 eslint。我的函数代码如下：

exports.onCreateActivityFeedItem = functions
.firestore
.document('/feed/{userId}/feedItems/{activityFeedItem')
.onCreate(async (snapshot, context) => {
console.log('Activity Feed Item Create', snapshot.data());
// 1) Get user connected to the feed
const userId = context.params.userId;
const userRef = admin.firestore().doc(`users/${userId}`);
const doc = await userRef.get();
// 2) Once we have user, check if the have notification token
//send notification if they have a token
const androidNotificationToken = doc.data().androidNotificationToken;
const createdActivityFeedItem = snapshot.data();
if(androidNotificationToken){
//send the notification
sendNotification(androidNotificationToken, createdActivityFeedItem);
}else{
console.log("No token for user, cannot send notification");
}
function sendNotification(androidNotificationToken, activityFeedItem){
let body;
// 3) switch body value based off of notification type
switch (activityFeedItem.type){
case "comment":
body = `${activityFeedItem.username} replied: ${activityFeedItem.commentData}`;
break;
case "like":
body = `${activityFeedItem.username} liked your post`;
break;
case "follow":
body = `${activityFeedItem.username} started following your pet`;
break;
default:
break;
}
// 4) Create message for push notification
const message = {
notification: { body },
token: androidNotificationToken,
data: { recipient: userId }
};
// 5) Send message with admin.messaging()
admin
.messaging()
.send(message)
.then(response => {
// Response is a message ID string
console.log("Successfully sent message", response);
//return 1;   //Last edition trying to fix bug
}).catch(error => {
console.log("Error sending message", error);
});
}
});

Answer 1

更改以下内容：

admin
.messaging()
.send(message)
.then(response => {
// Response is a message ID string
console.log("Successfully sent message", response);
//return 1;   //Last edition trying to fix bug
}).catch(error => {
console.log("Error sending message", error);
});
}

进入这个：

return admin
.messaging()
.send(message)
.then(response => {
// Response is a message ID string
console.log("Successfully sent message", response);
// return 1;   //Last edition trying to fix bug
}).catch(error => {
console.log("Error sending message", error);
});
}

此外，您在document中缺少}：

改变：document('/feed/{userId}/feedItems/{activityFeedItem')

进入这个：

document('/feed/{userId}/feedItems/{activityFeedItem}')