我是新来的,所以我知道我没有任何可信度。我是一名艺术家,也是编程新手,所以我理解如果没有人会接受这个。我发布这个机会,这是一个简单的问题。-S
这是创建多个标记的代码(主要来自谷歌开发者网站)。它工作正常,并为每个标记创建一个自定义图标。单击每个标记时应播放不同的音频文件(现在只有创建的最后一个标记)。我还想在播放音频文件时更改图标。我正在使用javascript和声音管理器2来播放音频 - 但我感兴趣的是:如何引用数组中的每个标记,以便可以播放分配给该特定标记的特定音频文件?
我希望我在没有XML和数据库的情况下做到这一点。-萨宾
以下是相关代码:
setMarkers(map, beaches);
}
var beaches = [
['Devotion', 40.710431,-73.948432, 0],
['Tester', 40.711223,-73.958416, 1],
];
function setMarkers(map, locations) {
var image = new google.maps.MarkerImage('biker.png',
// This marker is 20 pixels wide by 32 pixels tall.
new google.maps.Size(32, 32),
// The origin for this image is 0,0.
new google.maps.Point(0,0),
// The anchor for this image is the base of the flagpole at 0,32.
new google.maps.Point(0, 32)
);
var newimage = new google.maps.MarkerImage('biker_click.png',
// This marker is 20 pixels wide by 32 pixels tall.
new google.maps.Size(32, 32),
// The origin for this image is 0,0.
new google.maps.Point(0,0),
// The anchor for this image is the base of the flagpole at 0,32.
new google.maps.Point(0, 32)
);
var shape = {
coord: [1, 1, 1, 20, 18, 20, 18 , 1],
type: 'poly'
};
for (var i = 0; i < locations.length; i++) {
var beach = locations[i];
var myLatLng = new google.maps.LatLng(beach[1], beach[2]);
var marker = new google.maps.Marker({
position: myLatLng,
map: map,
icon: image,
shape: shape,
title: beach[0],
zIndex: beach[3],
});
}
function markerClick() {
console.log('click');
}
google.maps.event.addListener(marker, 'click', markerClick);
function markerClick() {
var playing = sm2.toggle('http://mm1.ellieirons.com/wp-content/uploads/2012/03/beeps_bubbles.mp3', true);
if (playing) {
this.setIcon(newimage);
} else {
this.setIcon(image);
}
}
假设您有一个 URL 数组:
var sounds = ["http://mm1.ellieirons.com/wp-content/uploads/2012/03/beeps_bubbles.mp3",
"http://mm1.ellieirons.com/wp-content/uploads/2012/03/beeps_bubbles2.mp3"];
然后你可以尝试这样的事情:
for (var i = 0; i < locations.length; i++) {
var beach = locations[i];
var myLatLng = new google.maps.LatLng(beach[1], beach[2]);
var marker = new google.maps.Marker({
position: myLatLng,
map: map,
icon: image,
shape: shape,
title: beach[0],
zIndex: beach[3]
});
marker.sound = sounds[i]; //Storing associated sound in marker
google.maps.event.addListener(marker, 'click', markerClick);
}
并将处理程序修改为:
function markerClick() {
var playing = sm2.toggle(this.sound, true);
if (playing) {
this.setIcon(newimage);
} else {
this.setIcon(image);
}
}
像这样的东西。
var beaches = [
['Devotion', 40.710431,-73.948432, 0, 'sound1.mp3'],
['Tester', 40.711223,-73.958416, 1, 'sound2.mp3'],
];
// ...
for (var i = 0; i < locations.length; i++) {
var beach = locations[i];
var myLatLng = new google.maps.LatLng(beach[1], beach[2]);
var marker = new google.maps.Marker({
position: myLatLng,
map: map,
icon: image,
shape: shape,
title: beach[0],
zIndex: beach[3],
});
google.maps.event.addListener(marker, 'click', function() {
playSound(beach[4]);
});
}
因为您在循环中定义了一个匿名函数,所以它可以访问循环的变量(它是一个"闭包")。 您将声音的名称添加到与海滩关联的数据中,然后将其从闭包传递到函数(我称之为playSound),这实际上会导致它播放。
希望这有帮助,这不是一个完整的食谱。