我试图用youtube javascript api v3编写一个简单的youtube请求来搜索视频。
这是源代码:
<!DOCTYPE html>
<html>
<head>
<script type="text/javascript">
function showResponse(response) {
var responseString = JSON.stringify(response, '', 2);
document.getElementById('response').innerHTML += responseString;
}
// Called automatically when JavaScript client library is loaded.
function onClientLoad() {
gapi.client.load('youtube', 'v3', onYouTubeApiLoad);
}
// Called automatically when YouTube API interface is loaded
function onYouTubeApiLoad() {
// This API key is intended for use only in this lesson.
gapi.client.setApiKey('API_KEY');
search();
}
function search() {
var request = gapi.client.youtube.search.list({
part: 'snippet',
q:'U2'
});
// Send the request to the API server,
// and invoke onSearchRepsonse() with the response.
request.execute(onSearchResponse);
}
// Called automatically with the response of the YouTube API request.
function onSearchResponse(response) {
showResponse(response);
}
</script>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.2/jquery.min.js"></script>
<script src="https://apis.google.com/js/client.js?onload=onClientLoad" type="text/javascript"></script>
</head>
<body>
<pre id="response"></pre>
</body>
</html>
当我在谷歌chrome(更新)上加载这个页面时,什么都没有发生,页面保持空白。我已经请求了浏览器应用程序的API密钥(带有referer),并复制到方法gap.client.setApiKey.中
有人能帮我吗?
感谢
在这里尝试这个例子
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8"/>
<title>Google AJAX Search API Sample</title>
<script type="text/javascript" src="http://www.google.com/jsapi"></script>
<script type="text/javascript">
// How to search through a YouTube channel aka http://www.youtube.com/members
google.load('search', '1');
function OnLoad() {
// create a search control
var searchControl = new google.search.SearchControl();
// So the results are expanded by default
options = new google.search.SearcherOptions();
options.setExpandMode(google.search.SearchControl.EXPAND_MODE_OPEN);
// Create a video searcher and add it to the control
searchControl.addSearcher(new google.search.VideoSearch(), options);
// Draw the control onto the page
searchControl.draw(document.getElementById("content"));
// Search
searchControl.execute("U2");
}
google.setOnLoadCallback(OnLoad);
</script>
</head>
<body style="font-family: Arial;border: 0 none;">
<div id="content">Loading...</div>
</body>
</html>
当您使用<script src="https://apis.google.com/js/client.js?onload=onClientLoad"..></script>
你必须在网上的某个地方上传html文件,或者在你的电脑上使用XAMPP
要使用html搜索YT视频,在PC上使用Javascript,正如我所知,我们需要使用其他编码:
1-对于API 2.0版,使用与此类似的javascript代码。除了API KEY v3。
2-为此目的使用jQuery方法"$.get(..)"。
请参阅:http://play-videos.url.ph/v3/search-50-videos.html
有关更多详细信息,请参阅(我的帖子"搜索视频的Java脚本"):
http://phanhung20.blogspot.com/2015_09_01_archive.html
var maxRes = 50;
function searchQ(){
query = document.getElementById('queryText').value;
email = 'https://www.googleapis.com/youtube/v3/search?part=snippet&maxResults=50'+
'&order=viewCount&q='+ query + '&key=****YOUR API3 KEY*****'+
'&callback=myPlan';
var oldsearchS = document.getElementById('searchS');
if(oldsearchS){
oldsearchS.parentNode.removeChild(oldsearchS);
}
var s = document.createElement('script');
s.setAttribute('src', email);
s.setAttribute('id','searchS');
s.setAttribute('type','text/javascript');
document.getElementsByTagName('head')[0].appendChild(s);
}
function myPlan(response){
for (var i=0; i<maxRes;i++){
var videoID=response.items[i].id.videoId;
if(typeof videoID != 'undefined'){
var title=response.items[i].snippet.title;
var links = '<br><img src="http://img.youtube.com/vi/'+ videoID +
'/default.jpg" width="80" height="60">'+
'<br>'+(i+1)+ '. <a href="#" onclick="playVid(''+ videoID +
'');return false;">'+ title + '</a><br>';
document.getElementById('list1a').innerHTML += links ;
}
}
}
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8">
</head>
<body>
<input type="text" value="abba" id="queryText" size="80">
<button type="button" onclick="searchQ()">Search 50 videos</button>
<br><br>
<div id='list1a' style="width:750px;height:300px;overflow:auto;
text-align:left;background-color:#eee;line-height:150%;padding:10px">
</div>
我使用了Tom发布的原始代码,它给了我403访问权限错误。当我回到我的api控制台&检查了我的api访问时间,它已经过期了。所以我重新创建了api的访问时间。它重新创造了新的时间。代码运行良好,结果良好。
简单地说,我必须从web服务器发出请求。
感谢大家的回复