当不在视图文件夹中时，如何将外部GSP或模板包括在GSP文件中？
是的，您可以轻松地做到这一点。在这里，你去：
import grails.gsp.PageRenderer
class MyLib {
static namespace = "foo"
static defaultEncodeAs = "raw"
PageRenderer groovyPageRenderer
def externalTemplate = { attrs, body ->
String externalFilePath = attrs.externalPath
/*
* Put content of that external template to a file inside grails-app/views folder
* with a temporary unique name appended by current timestamp
*/
String temporaryFileName = "_external-" + System.currentTimeMillis() + ".gsp"
File temporaryFile = new File("./grails-app/views/temp/$temporaryFileName")
/*
* Copy content of external file path to the temporary file in views folder.
* This is required since the groovyPageRenderer can compile any GSP located inside
* the views folder.
*/
temporaryFile.text << new File(externalFilePath).text
/*
* Now compile the content of the external GSP code and render it
*/
out << groovyPageRenderer.render([template: "/temp/$temporaryFileName", model: attrs.model])
// Delete the file finally
temporaryFile.delete()
}
}
现在，在您要包含外部GSP的实际GSP中，您可以写下：
<body>
<foo:externalTemplate externalPath="/home/user/anyExternalFile.gsp" model="${[status: 1}" />
</body>
我知道我迟到了这个答复，但是当我们尝试将报告视图放在视图文件夹之外时，我遇到了这个问题。
我们无法使用上述方法，因为我们正在运行JAR软件包，并且无法在Views Folder中创建文件。
这是Grails 4
的解决方案首先注射
def groovyPagesTemplateEngine
def groovyPageLayoutFinder
然后在您的控制器中
File externalFile = new File("/path/to/file.gsp")
if(externalFile && externalFile.exists()){
GroovyPageView groovyPageView = new GroovyPageView()
LinkedHashMap model = [:]
Template template = groovyPagesTemplateEngine.createTemplate(externalFile.text, externalFileName)
groovyPageView.setServletContext(getServletContext())
groovyPageView.setTemplate(template)
groovyPageView.setApplicationContext(getApplicationContext())
groovyPageView.setTemplateEngine(groovyPagesTemplateEngine)
groovyPageView.afterPropertiesSet()
request.setAttribute GrailsLayoutDecoratorMapper.LAYOUT_ATTRIBUTE, null
GrailsLayoutView grailsLayoutView = new GrailsLayoutView(groovyPageLayoutFinder, groovyPageView)
grailsLayoutView.render model, webRequest.getCurrentRequest(), webRequest.getResponse()
webRequest.renderView = false
return
}
else {
// something that shows error
render "not found"
}