我正在尝试使用sendgrid v3 api清除弹跳,在CLI中使用curl时可以正常工作,这是命令:
curl -v -X DELETE -d '{"delete_all": true}' -H "Content-Type: application/json" -H "Authorization: Bearer SG.mykey" "https://api.sendgrid.com/v3/suppression/bounces"
但是,当尝试使用Symfony2/guzzle启动它时,我会遇到一个不好的请求错误,但是请求似乎还可以,这是(string) $request
的输出:
"""
DELETE /v3/suppression/bounces HTTP/1.1rn
Host: api.sendgrid.comrn
Authorization: Bearer SG.mykeyrn
User-Agent: Guzzle/3.9.3 curl/7.35.0 PHP/5.5.9-1ubuntu4.17rn
Accept: application/jsonrn
Content-Length: 20rn
rn
{"delete_all": true}
"""
和例外:
[GuzzleHttpExceptionClientErrorResponseException]
Client error response
[status code] 400
[reason phrase] BAD REQUEST
[url] https://api.sendgrid.com/v3/suppression/bounces
使用GET方法时,它可以正常工作,并且会返回所有弹跳。
这是Guzzle代码:
$request = $this->httpClient->delete('/v3/suppression/bounces', null, '{"delete_all": true}');
$response = $request->send();
http客户端是用https://api.sendgrid.com base url。
我认为您的问题是您在只有两个时发送3个参数以删除,而是您需要做的就是在选项阵列中传递身体。
$response = $this->httpClient->delete(
'/v3/suppression/bounces',
[
'body' => json_encode(['delete_all', true]),
'Authorization' => 'Basic ' . base64_encode($username . ':' . $password),
'content-type' => 'application/json'
]
);
guzzle选项文档
回答自己。问题很明显:没有设置内容类型的标题,"接受"是。我不在乎此标头,因为在使用此API的GET方法时,您不必通过它。因此,现在在调试我的请求对象时:
"""
DELETE /v3/suppression/bounces HTTP/1.1rn
Host: api.sendgrid.comrn
Authorization: Bearer SG.mykeyrn
Content-Type: application/jsonrn
Content-Length: 20rn
User-Agent: Guzzle/3.9.3 curl/7.35.0 PHP/5.5.9-1ubuntu4.17rn
Accept: application/jsonrn
rn
{"delete_all": true}
"""