Java JFrame tiles

Question

我目前正在尝试使用菱形和正方形算法制作分形地形生成器。我已经完成了算法（我想），但我不知道如何很好地使用JFrames。

我该如何让它显示瓷砖？

package fractal.terrain;
import java.util.Random;
public class Main {
    public int mapSize = 257;
    public static void main(String[] args) {
        Main m = new Main();
        double tileData[][] = new double[m.mapSize][m.mapSize];
        Random r = new Random();
        final double seed = r.nextInt(10000 - 500 + 1);
        System.out.println("The seed is " + seed);
        tileData[0][0] = tileData[0][m.mapSize - 1] = tileData[m.mapSize - 1][0]
                = tileData[m.mapSize - 1][m.mapSize - 1] = seed;
        double h = 10000.0;
        for (int sideLength = m.mapSize - 1; sideLength >= 2; sideLength /= 2) {
            int halfSide = sideLength / 2;
            for (int x = 0; x < m.mapSize - 1; x += sideLength) {
                for (int y = 0; y < m.mapSize - 1; y += sideLength) {
                    double avg = tileData[x][y]
                            + tileData[x + sideLength][y]
                            + tileData[x][y + sideLength]
                            + tileData[x + sideLength][y + sideLength];
                    avg /= 4.0;
                    tileData[x + halfSide][y + halfSide] = avg + (r.nextDouble() * 2 * h) - h;
                }
            }
            for (int x = 0; x < m.mapSize - 1; x += halfSide) {
                for (int y = (x + halfSide) % sideLength; y < m.mapSize - 1; y += sideLength) {
                    double avg = tileData[(x - halfSide + m.mapSize) % m.mapSize][y]
                            + tileData[(x + halfSide) % m.mapSize][y]
                            + tileData[x][(y + halfSide) % m.mapSize]
                            + tileData[x][(y - halfSide + m.mapSize) % m.mapSize];
                    avg /= 4.0;
                    avg = avg + (r.nextDouble() * 2 * h) - h;
                    tileData[x][y] = avg;
                    if (x == 0) {
                        tileData[m.mapSize - 1][y] = avg;
                    }
                    if (y == 0) {
                        tileData[x][m.mapSize - 1] = avg;
                    }
                }
            }
        }
    }
}

Answer 1

覆盖JPanel上的draw方法，并在数组中循环为每个值绘制不同颜色的矩形。

@Override
protected void paintComponent(Graphics g){
    super.paintComponent(g);
    for (int x = 0; x < m.mapSize; x++) {
        for (int y = 0; y < m.mapSize; y++) {
            //check each tile and assign in a color based on its value
            if(tileData[x][y] == aCertainNumber){
                g.setColor();
            }
            g.fillRect(x*10, y*10, 10, 10);
        }
    }

这应该显示每个瓦片10像素乘10像素的

你也可以用输出到图像

BufferedImage map = new BufferedImage(mapSize, mapSize,BufferedImage.TYPE_INT_RGB);
    for (int x = 0; x < mapSize; x++) {
        for (int y = 0; y < mapSize; y++) {
            if(mapData[x][y]==aCertainNumber)
            map.setRGB(x, y, theColorYouWant.getRGB());
        }
    }