如何在<Objects> POST 方法(RestTemplate) 中将列表作为正文传递

Question

我正在尝试使用RESTTEMPLATE提出发布请求，问题是API是在身体中接受List<Users>作为邮政请求

public class Users {
    String id;
    String name;
    String gender;
}

我已经添加了

的元素

List<Users> userList=new ArrayList<Users>();
userList.add(new Users("1","AA","Male"));
userList.add(new Users("2","BB","Male"));
userList.add(new Users("3","CC","Female"));

AS

HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);
HttpEntity<String> entity = new HttpEntity<>(headers);
ResponseEntity<String> response =  restTemplate.postForEntity(URL.toString(), HttpMethod.POST, entity, String.class);

在这里我应该如何将我的用户列表传递到请求主体？

Answer 1

您需要在httpentity中传递数据。

String userJsonList = objectMapper.writeValueAsString(userList);
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);
HttpEntity<String> entity = new HttpEntity<>(userJsonList, headers);
ResponseEntity<String> response =  restTemplate.postForEntity(URL.toString(), HttpMethod.POST, entity, String.class);

因此，基本上它将将数据传递为JSON字符串。

Answer 2

对于发布请求，您可以使用" method = requestmethod.post"或@post注释。对于列表对象，请选中以下代码。它将起作用。

public ResponseEntity<List<Users>> methodName(@QueryParam("id") String id){
List<Users> userList=new ArrayList<Users>();
userList.add(new Users("1","AA","Male"));
userList.add(new Users("2","BB","Male"));
userList.add(new Users("3","CC","Female"));
return new ResponseEntity<List<Users>>(userList, HttpStatus.OK);
}