从cookie获取数据

Question

我正在使用此代码输出到我的错误日志：

ob_start();
var_dump($_COOKIE['agl-values']);
error_log(ob_get_clean());

输出为：

[02-APR-2018 16:12:58 UTC] String(321( " {" latitude "：" 42.2470259 "，"经度"：" - 71.1755274 "，"，"高度"： " nan " nan "，"， "准确"准确"：， " altitudeaccuracy "：" nan "，" heading "：" nan "，" speed "：" nan "， " error_code "：error_message "：" "，" php_time "：1522684274，" php_date "：" 2018-04-02 15:51:14 "，" php_date_format "：" y-m-d H：i：i：s "，" user_id "：0}"

[02-APR-2018 16:12:58 UTC] String(321( " {" latitude "：" 42.2470259 "，"经度"：" - 71.1755274 "，"，"高度"： " nan " nan "，"， "准确"准确"：， " altitudeaccuracy "：" nan "，" heading "：" nan "，" speed "：" nan "， " error_code "：error_message "：" "，" php_time "：1522684274，" php_date "：" 2018-04-02 15:51:14 "，" php_date_format "：" y-m-d H：i：i：s "，" user_id "：0}"

[02-APR-2018 16:12:58 UTC] String(321( " {" latitude "：" 42.2470259 "，"经度"：" - 71.1755274 "，"，"高度"： " nan " nan "，"， "准确"准确"：， " altitudeaccuracy "：" nan "，" heading "：" nan "，" speed "：" nan "， " error_code "：error_message "：" "，" php_time "：1522684274，" php_date "：" 2018-04-02 15:51:14 "，" php_date_format "：" y-m-d H：i：i：s "，" user_id "：0}"

[02-APR-2018 16:12:58 UTC] String(321( " {" latitude "：" 42.2470259 "，"经度"：" - 71.1755274 "，"，"高度"： " nan " nan "，"， "准确"准确"：， " altitudeaccuracy "：" nan "，" heading "：" nan "，" speed "：" nan "， " error_code "：error_message "：" "，" php_time "：1522684274，" php_date "：" 2018-04-02 15:51:14 "，" php_date_format "：" y-m-d H：i：i：s "，" user_id "：0}"

我只需要访问纬度和经度变量。我如何隔离其中一个cookie，然后如何将其变成JSON？

update

我检查了json_last_error()，它告诉我字符串有语法错误 - 是否是逃脱的双引号？

Answer 1

看起来JSON("(中有一些逃脱的引号，这意味着json_decode将在语法错误中失败。尝试使用str_replace将其更改为常规报价("(：

json_decode(str_replace('"', '"', $_COOKIE['agl-values']))

，要获得纬度和经度，请执行这样的事情：

$aglValues = json_decode(str_replace('"', '"', $_COOKIE['agl-values']));
var_dump($aglValues->latitude);
var_dump($aglValues->longitude);

Answer 2

cookie已经处于JSON格式，您需要正确解码。

使用：

print_r(json_decode($_COOKIE['agl-values'], true));

或单个值：

echo json_decode($_COOKIE['agl-values'], true)['latitude'];

使用默认JSON DEDODE对象：

echo json_decode($_COOKIE['agl-values'])->latitude;

Answer 3

看起来它是作为字符串存储的。转换为JSON对象，然后参考：

$value = json_decode($_COOKIE['agl-values']);
echo $value->longitude . ' ' . $value->latitude;

update

这是您的字符串的直接示例：

php > $var = json_decode("{"latitude":"42.2470259","longitude":"-71.1755274","altitude":"NaN","accuracy":"29","altitudeAccuracy":"NaN","heading":"NaN","speed":"NaN","error_code":"","error_message":"","php_time":1522684274,"php_date":"2018-04-02 15:51:14","php_date_format":"Y-m-d H:i:s","user_id":0}");
php > echo $var->longitude;
-71.1755274