我有字典
from collections import OrderedDict
md = {"r3":"piz","r1":"pic","r9":"piz","r12":"pic","r19":"lia","r2":"kurcc","r21":"jes","r99":"pic","r111":"kurcc","r116":"kurcc","r211":"ar","r221":"buc"}
print (OrderedDict(sorted(md.items(), key=lambda t: t[0])))
我想从最低数字排序。但我得到了
OrderedDict([('r1', 'pic'), ('r111', 'kurcc'), ('r116', 'kurcc'), ('r12', 'pic'), ('r19', 'lia'), ('r2', 'kurcc'), ('r21', 'jes'), ('r211', 'ar'), ('r221', 'buc'), ('r3', 'piz'), ('r9', 'piz'), ('r99', 'pic')])
我应该如何更改我的代码以具有 r1,r2,r3 顺序?
如果所有键的形式都是'r???'
,???
整数,我们可以使用以下排序键:
OrderedDict(sorted(md.items(), key=lambda t:int(t[0][1:])))
所以在这里,我们首先像你自己一样t[0]
拿钥匙。接下来,我们获取从索引 1 开始的子字符串(因此我们删除了'r'
(,最后我们将其转换为int(..)
以执行数值比较。
这将生成:
>>> OrderedDict(sorted(md.items(), key=lambda t: int(t[0][1:])))
OrderedDict([('r1', 'pic'), ('r2', 'kurcc'), ('r3', 'piz'), ('r9', 'piz'), ('r12', 'pic'), ('r19', 'lia'), ('r21', 'jes'), ('r99', 'pic'), ('r111', 'kurcc'), ('r116', 'kurcc'), ('r211', 'ar'), ('r221', 'buc')])