如何基于唯一元素连接两个节点集

Question

我有一个大的xml文件，其中包含不同的节点集，我需要根据两个节点包含的唯一元素值使用xsl进行组合。

下面是需要转换的 xml 文件的示例：

<root>
  <node1>
    <funds>
      <fund>
        <FundId>a</FundId>
        <FundName>fund a</FundName>
        <SomeInfo>some info</SomeInfo>
      </fund>
      <fund>
        <FundId>b</FundId>
        <FundName>fund b</FundName>
        <SomeInfo>some info</SomeInfo>
      </fund>
      <fund>
        <FundId>c</FundId>
        <FundName>fund c</FundName>
        <SomeInfo>some info</SomeInfo>
      </fund>
    </funds>
  </node1>
  <node2>
    <funds>
      <fund>
        <FundId>a</FundId>
        <MaxInvestmentAmount>200</MaxInvestmentAmount>
        <MinInvestmentAmount>1</MinInvestmentAmount>
      </fund>
      <fund>
        <FundId>b</FundId>
        <MaxInvestmentAmount>100</MaxInvestmentAmount>
        <MinInvestmentAmount>5</MinInvestmentAmount>
      </fund>
      <fund>
        <FundId>c</FundId>
        <MaxInvestmentAmount>50</MaxInvestmentAmount>
        <MinInvestmentAmount>20</MinInvestmentAmount>
      </fund>
    </funds>
  </node2>
</root>

这是所需的输出：

<node>
    <funds>
        <fund>
            <FundId>a<FundId/>
            <FundName>fund a</FundName>
            <SomeInfo>some info</SomeInfo>
            <MaxInvestmentAmount>200</MaxInvestmentAmount>
            <MinInvestmentAmount>1</MinInvestmentAmount>
        </fund>
        <fund>
            <FundId>b<FundId/>
            <FundName>fund b</FundName>
            <SomeInfo>some info</SomeInfo>
            <MaxInvestmentAmount>100</MaxInvestmentAmount>
            <MinInvestmentAmount>5</MinInvestmentAmount>
        </fund>
        <fund>
            <FundId>c<FundId/>
            <FundName>fund c</FundName>
            <SomeInfo>some info</SomeInfo>
            <MaxInvestmentAmount>50</MaxInvestmentAmount>
            <MinInvestmentAmount>20</MinInvestmentAmount>
        </fund>
    </funds>
</node>

我尝试

过模板匹配，但这似乎不像我尝试的那样有效，因为两个节点具有相同的内部节点名称，因此它们不断相互覆盖。

Answer 1

实现此目的的一个可靠方法是对<fund>元素使用xsl:key，并将FundId作为键。此方法的一个相关限制是仅合并第一个子元素(此处<node1>(的FundId键。如果其他子元素包含更多值，则此方法将无法按预期工作。

下面是 XSLT-1.0 样式表：

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" indent="yes" />
  <xsl:key name="keyFund" match="fund" use="FundId" />   
  <xsl:template match="/root">
    <node>
        <funds>
            <xsl:for-each select="*[1]/funds/fund">
                <fund>
                    <xsl:copy-of select="FundId" />
                    <xsl:for-each select="key('keyFund',FundId)">
                        <xsl:copy-of select="current()/*[not(self::FundId)]" />
                    </xsl:for-each>
                </fund>
            </xsl:for-each>
        </funds>
    </node>
  </xsl:template>
</xsl:stylesheet>

其输出为：

<?xml version="1.0"?>
<node>
    <funds>
        <fund>
            <FundId>a</FundId>
            <FundName>fund a</FundName>
            <SomeInfo>some info</SomeInfo>
            <MaxInvestmentAmount>200</MaxInvestmentAmount>
            <MinInvestmentAmount>1</MinInvestmentAmount>
        </fund>
        <fund>
            <FundId>b</FundId>
            <FundName>fund b</FundName>
            <SomeInfo>some info</SomeInfo>
            <MaxInvestmentAmount>100</MaxInvestmentAmount>
            <MinInvestmentAmount>5</MinInvestmentAmount>
        </fund>
        <fund>
            <FundId>c</FundId>
            <FundName>fund c</FundName>
            <SomeInfo>some info</SomeInfo>
            <MaxInvestmentAmount>50</MaxInvestmentAmount>
            <MinInvestmentAmount>20</MinInvestmentAmount>
        </fund>
    </funds>
</node>