我希望你一切都好!
我需要使用RestSharp执行邮政请求,以下要添加要添加到请求的正文。这比我以前做过的帖子请求要复杂。
我请求协助的复杂帖子:
{
"contextInfoId": "string",
"userId": "string",
"specificOs": "string",
"buildPlatform": "string",
"deviceName": "string",
"deviceId": "string",
"token": "string",
"loginInfo": {
"loginInfoId": "string",
"loginDate": "2019-03-14T06:21:39.693Z"
}
}
对我来说这个问题是'logininfo:'必须提供的方式
我已经使用以下代码添加了基本的帖子主体:
//Add json data/body
request.AddJsonBody(new { buProfileId ="1", divisionNames = "IDC", businessUnitNames = "XYZ", processGroupNames = "ABC", systemOrProjectName = "Test", customername = "User" });
上面的C#代码适合下面的身体。
{
"buProfileId": "string",
"divisionNames": "string",
"businessUnitNames": "string",
"processGroupNames": "string",
"systemOrProjectName": "string",
"customername": "string"
}
有人可以让我知道如何实现复杂的后操作。
您可以创建一个JSON对象并将您的值分配给它,然后您可以序列化JSON并发送到主体
public class LoginInfo
{
public string loginInfoId { get; set; }
public DateTime loginDate { get; set; }
}
public class Context
{
public string contextInfoId { get; set; }
public string userId { get; set; }
public string specificOs { get; set; }
public string buildPlatform { get; set; }
public string deviceName { get; set; }
public string deviceId { get; set; }
public string token { get; set; }
public LoginInfo loginInfo { get; set; }
}
public IRestResponse Post_New_RequestType(string context, string user_ID, string Specific_Os, string Build_Platfrom, string Device_Name, string device_Id, string Token_Value, string login_infoId, DateTime Login_Date)
{
Context tmp = new Context();
tmp.contextInfoId = context;
tmp.userId = user_ID;
tmp.specificOs = Specific_Os;
tmp.buildPlatform = Build_Platfrom;
tmp.deviceName = Device_Name;
tmp.deviceId = device_Id;
tmp.token = Token_Value;
tmp.loginInfo.loginInfoId = login_infoId;
tmp.loginInfo.loginDate = Login_Date;
string json = JsonConvert.SerializeObject(tmp);
var Client = new RestClient(HostUrl);
var request = new RestRequest(Method.POST);
request.Resource = string.Format("/api/example");
request.AddParameter("application/json", json, ParameterType.RequestBody);
IRestResponse response = Client.Execute(request);
return response;
}