我的代码:
abc = {
'Name':emp_name,
'Id no':emp_idno,
'Leave taken':k,
'Leave reqd':b,
'Total days of leave':total,
'Reason':reason
}
我的输出为:
id, name, total, reqason, leave taken, leave reqd
我希望输出按以下顺序:
Name, id, leave taken, leave reqd, total, reason
我对此感到困惑,如果有人可以帮助我,那就太好了。
我的CSV代码
dl = {'Name':emp_name,'Id no':emp_idno, 'Leave taken':k, 'Leave
> reqd':b, 'Reason':reason}
>
>
> key_list = ['Name', 'Id no', 'Leave taken', 'Leave reqd', 'Reason'] abc = { 'Name':emp_name, 'Id no':emp_idno, 'Leave taken':k,
> 'Leave reqd':b, 'Reason':reason }
>
> for k in key_list:
> print abc[k] Lst.append(k)
>
> keys = Lst[0].keys() with open('employee.csv', 'wb') as output_file:
> dict_writer = csv.DictWriter(output_file, keys)
> dict_writer.writeheader()
> dict_writer.writerows(Lst)
Dictionaries
默认情况下是无序的。
您需要ordered
Dicitionary
。
请参阅collections.OrderedDict
eg:
from collections import OrderedDict
d = OrderedDict()
d['Name'] = emp_name
d['Id no'] = emp_idno
d['Leave taken'] = k
print d
一个简单的黑客可以将键存储在列表中。
key_list = ['Name', 'Id no', 'Leave taken', 'Leave reqd', 'Total days of leave', 'Reason']
abc = {
'Name':emp_name,
'Id no':emp_idno,
'Leave taken':k,
'Leave reqd':b,
'Total days of leave':total,
'Reason':reason
}
for k in key_list:
print abc[k]