given:
def someService = Mock(SomeService)
1 * someService.processInput(argument1) >> output1
1 * someservice.processInput(argument2) >> output2
如何在一个语句中使用它with
带有不同参数的子句。例如:
2 * someService.processInput(argument1) >>> [output1, output2]
我相信
目前在斯波克不可能以您可能期望的优雅方式进行。我只提出了如下内容:
def args = [arg1, arg2]
2 * service.processInput({ it == args.removeAt(0) }) >>> [out1, out2]
不确定它是否符合您的期望。以下是测试此方法的完整规范
class SOSpec extends Specification {
def "mock a method different arguments and different return values"() {
when:
def arg1 = "F"
def arg2 = "B"
def out1 = "Foo"
def out2 = "Bar"
def service = Mock(SomeService) {
def args = [arg1, arg2]
2 * processInput({ it == args.removeAt(0) }) >>> [out1, out2]
}
then:
service.processInput(arg1) == out1
service.processInput(arg2) == out2
}
}