如何从这个amazon模板中获得平均星级(例如5颗星中的4.3颗星((https://www.amazon.com/s/ref=sr_pg_1?fst=as%3Aoff&rh=n%3A1055398%2Cn%3A1063306%2K%3Aas&keywords=as&ie＝UTF8&qid=1532070774(。这是一个亚马逊产品页面。问题出现在第二个try/catch块上，并进行了复查。我附上了代码。我将感谢任何帮助。非常感谢。
import csv
from selenium import webdriver
from bs4 import BeautifulSoup
import requests
from lxml import html
import io
links = [
'https://www.amazon.com/s/ref=sr_pg_1?fst=as%3Aoff&rh=n%3A1055398%2Cn%3A1063306%2Ck%3Aas&keywords=as&ie=UTF8&qid=1532070774'
]
proxies = {
'http': 'http://218.50.2.102:8080',
'https': 'http://185.93.3.123:8080'
}
chrome_options = webdriver.ChromeOptions()
chrome_options.add_argument('--proxy-server="%s"' % ';'.join(['%s=%s' % (k, v) for k, v in proxies.items()]))
driver = webdriver.Chrome(executable_path="C:\UsersAndrei-PCDownloadswebdriverchromedriver.exe",
chrome_options=chrome_options)
header = ['Product title', 'Product price', 'Review', 'ASIN']
with open('csv/demo.csv', "w") as output:
writer = csv.writer(output)
writer.writerow(header)
for i in range(len(links)):
driver.get(links[i])
for x in range(0,23):
product_title = driver.find_elements_by_xpath('//li[@id="result_{}"]/div/div[3]/div/a'.format(x))
title = [x.text for x in product_title]
try:
price = driver.find_element_by_xpath('//li[@id="result_{}"]/div/div[5]/div/a/span[2]'.format(x)).text
except:
price = 'No price v2'
print('No price v2')
try:
review = driver.find_element_by_xpath('//li[@id="result_{}"]/div/div[6]/span'.format(x)).text()
except:
review = 'No review v1'
print('No review v1')
try:
asin = driver.find_element_by_id('result_{}'.format(x)).get_attribute('data-asin')
except:
asin = 'No asin'
print('No asin')
try:
data = [title[0], price, review, asin]
except:
print('no items v3 ')
with io.open('csv/demo.csv', "a", newline="", encoding="utf-8") as output:
writer = csv.writer(output)
writer.writerow(data)
print('I solved this link %s' % (links[i]))
print('Number of product %s' % (i + 1))
您可以使用以下代码获得费率：
stars = driver.find_element_by_class_name('a-icon-alt').get_attribute('textContent')